Electromagnets are made of soft iron because soft iron has:

1. low retentivity and high coercive force
2. high retentivity and high coercive force
3. low retentivity and low coercive force
4. high retentivity and low coercive force

Subtopic:  Magnetic Materials |
 61%
From NCERT
NEET - 2010
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A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is F, the net force on the remaining three arms of the loop is

1. 3F                 

2. -F

3. -3F               

4.  F

Subtopic:  Current Carrying Loop: Force & Torque |
 83%
From NCERT
NEET - 2010
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A current loop consists of two identical semicircular parts each of radius \(R\), one lying in the \(x\text-y\) plane, and the other in the \(x\text-z\) plane. If the current in the loop is \(i\), what will be the resultant magnetic field due to the two semicircular parts at their common centre?
1. \( \dfrac{\mu_0 i}{2 \sqrt{2} R} \) 2. \( \dfrac{\mu_0 i}{2 R} \)
3. \( \dfrac{\mu_0 i}{4 R} \) 4. \( \dfrac{\mu_0 i}{\sqrt{2} R}\)
Subtopic:  Magnetic Field due to various cases |
 66%
From NCERT
NEET - 2010
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A closely wound solenoid of 2000 turns and area of cross-section 1.5×10-4 m2 carries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field 5×10-2 T making an angle of 30° with the axis of the solenoid. The torque on the solenoid will be

(1) 3×10-3 Nm                                 

(2) 1.5×10-3 Nm

(3) 1.5×10-2 Nm                               

(4) 3×10-2 Nm

Subtopic:  Magnetic Moment |
 73%
From NCERT
NEET - 2010
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A particle having a mass of 10-2 kg carries a charge of 5×10-8 C. The particle is given an initial horizontal velocity of 105 ms-1 in the presence of electric field E and magnetic field B. To keep the particle moving in a horizontal direction, it is necessary that

(1) B should be perpendicular to the direction of velocity and E should be along the direction of velocity.

(2) Both B and E should be along the direction of velocity.

(3) Both B and E are mutually perpendicular and perpendicular to the direction of velocity.

(4) B should be along the direction of velocity and E should be perpendicular to the direction of velocity.

Which one of the following pairs of statements are possible?

1.   (1) and (3)                                       2.    (3) and (4)

3.   (2) and (3)                                       4.   (2) and (4)

Subtopic:  Lorentz Force |
 54%
From NCERT
NEET - 2010
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The magnetic moment of a diamagnetic atom is:

1. much greater than one.
2. one.
3. between zero and one. 
4. equal to zero.

Subtopic:  Magnetic Materials |
 68%
From NCERT
NEET - 2010
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Under the influence of a uniform magnetic field, a charged particle moves with constant speed v in a circle of radius R. The time period of rotation of the particle -

1. depends on v and not on R

2. depends on R and not on v

3. is independent of both v and R

4. depends on both v and R

Subtopic:  Lorentz Force |
 82%
From NCERT
NEET - 2009
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A rectangular, a square, a circular and an elliptical loop, all in the (x-y) plane, are moving out of a uniform magnetic field with a constant velocity, v=vi^. The magnetic field is directed along the negative z-axis direction. The induced emf, during the passage of these loops, out of the field region, will not remain constant for 

(1) the rectangular, circular and elliptical loops

(2) the circular and the elliptical loops

(3) only the elliptical loop

(4) any of the four loops

Subtopic:  Motional emf |
 70%
From NCERT
NEET - 2009
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The magnetic force acting on a charged particle of charge -2μC in a magnetic field of 2T acting in y-direction, when the particle velocity is 2i^+3j^×106 ms-1 is.

1. 8 N in -z-direction

2. 4 N in z-direction

3. 8 N in y-direction

4. 4 N in y-direction

Subtopic:  Lorentz Force |
 70%
From NCERT
NEET - 2009
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A closed-loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments PS, SR and RO are F1, F2 and F3 respectively and are in the plane of the paper and along with the directions shown the force on the segment QP is 

(a)F3+F1-F2

(b)F3-F12+F22

(c)F3-F12-F22

(d)F3-F1+F2

Subtopic:  Current Carrying Loop: Force & Torque |
 79%
From NCERT
NEET - 2008
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