A wire of resistance \(12~\Omega \text{m}^{-1}\) is bent to form a complete circle of radius \(10~\text{cm}\). The resistance between its two diametrically opposite points, \(A\) and \(B\) as shown in the figure, is:

                         
1. \(0.6\pi~\Omega\)
2. \(3~\Omega\)
3. \(6\pi~\Omega\)
4. \(6~\Omega\)

Subtopic:  Combination of Resistors |
 58%
From NCERT
NEET - 2009
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A student measures the terminal potential difference \((V)\) of a cell (of emf \(\varepsilon \) and internal resistance \(r\)) as a function of the current \((I)\) flowing through it. The slope and intercept of the graph between \(V\) and \(I,\) then respectively, equal:
1. \(\varepsilon \) and \(-r\)
2. \(-r\) and \(\varepsilon \)
3.  \(r\) and \(-\varepsilon \)
4. \(-\varepsilon \) and \(r\)

Subtopic:  EMF & Terminal Voltage |
 66%
From NCERT
NEET - 2009
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A galvanometer having a coil resistance of 60Ω shows full scale deflection when a current of 1.0A passes through it. It can be converted into an ammeter to read currents upto 5.0A by 

(a) putting in series resistance of 240Ω

(b) putting in parallel resistance of 240Ω

(c) putting in series resistance of 15Ω

(d) putting in parallel resistance of 15Ω

Subtopic:  Conversion to Ammeter & Voltmeter |
 75%
From NCERT
NEET - 2009
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See the electrical circuit shown in this figure. Which of the following equation is a correct equation for it?

1. ε1-i1+i2R-i1r1=0

2. ε2-i2r2-ε1-i1r1=0

3. -ε2-i1+i2R+i2r2=0

4. ε1-i1+i2R+i1r1=0

Subtopic:  Kirchoff's Voltage Law |
 71%
From NCERT
NEET - 2009
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A current of 3A flows through the 2Ω resistor shown in the circuit. The power dissipated in the 5Ω resistor is

 

(a) 4 W                                              (b) 2 W

(c) 1 W                                              (d) 5 W

Subtopic:  Heating Effects of Current |
 79%
From NCERT
NEET - 2008
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A wire of a certain material is streched slowly by ten per cent. Its new resistance and specific resistance become respectively 

(1) 1.2 times, 1.1 times

(2) 1.21 times,same 

(3) both remain the same

(4) 1.1 times, 1.1 times

Subtopic:  Derivation of Ohm's Law |
 83%
From NCERT
NEET - 2008
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A cell can be balanced against 110cm and 100 cm of potentiometer wire, respectively with and without being short-circuited through a resistance of 10 Ω. Its internal resistance is 

(1) 1.0 Ω

(2) 0.5 Ω

(3) 2.0 Ω

(4) zero 

Subtopic:  Grouping of Cells | Meter Bridge & Potentiometer |
 79%
From NCERT
NEET - 2008
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In the circuit shown, the current through the 4 Ω resistor is 1 A when the points P and M are connected to a DC voltage source. The potential difference  between the points M and N is 

1. 1.5 V 

2. 1.0 V

3. 0.5 V 

4. 3.2 V

Subtopic:  Kirchoff's Voltage Law |
 62%
From NCERT
NEET - 2008
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A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance of 2950 Ω in series. A full-scale deflection of 30 divisions is obtained in the galvanometer. In order to reduce this deflection to 20 divisions, the resistance in series should be 

(a) 5050Ω

(b) 5550 Ω

(c) 6050 Ω

(d) 4450Ω

Subtopic:  Conversion to Ammeter & Voltmeter |
 63%
From NCERT
NEET - 2008
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In the figure a long uniform potentiometer wire AB is having a constant potential gradient along its length. The null points for the two primary cells of emfs E1 and E2 connected in the manner shown are obtained at a distance of 120 cm and 300 cm from the end A. Find (i) E1E2and  position of null point for the cell E1.

How is the sensitivity of a potentiometer increased ?

 

Using Kirchoffs rules determine the value of unknown resistance R in the circuit so that no current flows through 4 Ω resistance. Also find the potential difference between A and D.

  

Subtopic:  Meter Bridge & Potentiometer |
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