Which of the following cation can not give borax bead test?

(a) ${\mathrm{Cr}}^{3+}$                          (b) ${\mathrm{Co}}^{2+}$

(c) ${\mathrm{Ag}}^{+}$                           (d) ${\mathrm{Mn}}^{2+}$

The incorrect statement regarding above reactions is :

(a) Al shows amphoteric character

(b) Gas 'P' and 'Q' are different

(d) Both X and Y are water soluble

(d) Gas Q is inflammable

The incorrect statement regarding above reactions is :

${\mathrm{BF}}_3+{\mathrm{LiAlH}}_4\stackrel{\mathrm{Ether}}{\to }\left(\mathrm{X}\right)+\mathrm{LiF}+{\mathrm{AlF}}_3$

(1) Twelve electrons are involed in bonding 

(2) Four, two centre-two electron bonds

(3) Two, three centre-two electron bonds 

(4) X does not react with ${\mathrm{NH}}_3$

The dissolution of $\mathrm{Al}(\mathrm{OH}{)}_3$ in a solution of $\mathrm{NaOH}$ results in the formation of -

1. ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_4{\left(\mathrm{OH}\right)}_2\right]}^{+}$       

2. $\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_3{\left(\mathrm{OH}\right)}_3\right]$

3. ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_2{\left(\mathrm{OH}\right)}_4\right]}^{-}$     

4. $\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6{\left(\mathrm{OH}\right)}_3\right]$

Borax is converted into crystalline boron by the following steps:

          $\mathrm{Borax}\stackrel{\mathrm{X}}{\to }{\mathrm{H}}_3{\mathrm{BO}}_3\stackrel{∆}{\to }{\mathrm{B}}_2{\mathrm{O}}_3\underset{∆}{\overset{\mathrm{Y}}{\to }}\mathrm{B}$

X and Y are respectively :

1. HCl, Mg                                 
2. HCl, C
3. C, Al 
4. HCl, Al

${\mathrm{BX}}_3+{\mathrm{NH}}_3\stackrel{\mathrm{R}.\mathrm{T}.}{\to }{\mathrm{BX}}_3 .{\mathrm{NH}}_3+$ Heat of adduct formation $\left(∆\mathrm{H}\right)$

The numerical value of $∆\mathrm{H}$ is found to be maximum for :

(1) ${\mathrm{BF}}_3$                               

(2) ${\mathrm{BCl}}_3$

(3) ${\mathrm{BBr}}_3$                             

(4) ${\mathrm{BI}}_3$

The number of carbon atoms per unit cell of diamond unit cell is:-

1. 4

2. 8

3. 6

4. 1

The correct order of ease of hydrolysis is :

1. CCl₄ < SiCl₄ < PCl₅ < AlCl₃

2. AlCl₃ < CCl₄ < PCl₅ < SiCl₄

3. CCl₄ < AlCl₃ < PCl₅ < SiCl₄

4. CCl₄ < AlCl₃ < SiCl₄ < PCl₅

Aluminium becomes passive in nitric acid because it-

1. Is a noble metal

2. Forms a thin film of oxide

3. Has a positive reduction potential

4.  None of the above

Hybridisation of boron in diborane is:

1.  $\mathrm{sp}$

2.  ${\mathrm{sp}}^2$

3.  ${\mathrm{sp}}^3$

4.  ${\mathrm{sp}}^3{\mathrm{d}}^2$