The degeneracy of d-orbitals is lost under:

(I) Strong field ligand                 (II) Weak field ligand

(III) Mixed field ligand                 (IV) Chelate

Choose the correct code:

(1) I,II and IV                                 

(2) I and II

(3) I,II,III and IV                             

(4) I,II and III

Which of the following isomerism, exhibited by $\left[{\mathrm{CrCl}}_2\right(\mathrm{OH}{)}_2\left({\mathrm{NH}}_3{)}_2\right]$?

(1)Ionization     

(2) Geometrical

(3) Hydrate       

(4) Linkage

How many geometrical isomers and stereoisomers are possible for $\left[\mathrm{Pt}\right({\mathrm{NO}}_2\left)\right({\mathrm{NH}}_3\left)\right({\mathrm{NH}}_2\mathrm{OH}\left)\right(\mathrm{Py}){]}^{+ }\mathrm{and} [\mathrm{Pt}\left(\mathrm{Br}\right)\left(\mathrm{Cl}\right)\left(\mathrm{I}\right)\left({\mathrm{NO}}_2\right)\left({\mathrm{NH}}_3\right)\left(\mathrm{Py}\right)]$    respectively?

(a) 3 and 15                 (b)  3 and 30

(c) 4 and 15                  (d) 4 and 30 

 A compound that form two stereoisomer is -

(I) $\left[\mathrm{Cr}\right({\mathrm{NO}}_3{)}_3\left({\mathrm{NH}}_3{)}_3\right]$     

(II) ${\mathrm{K}}_3\left[\mathrm{Fe}\right({\mathrm{C}}_2{\mathrm{O}}_4{)}_3]$

(III) $\left[{\mathrm{CoCl}}_2\right(\mathrm{en}{)}_2{]}^{+}$       

(IV) $\left[\mathrm{CoBrCl}\right(\mathrm{ox}{)}_2{]}^{3-}$

(1)I only     

(2) I and II   

(3) III and IV   

(4) All of these  

Three arrangements are shown for the complex $\left[{\mathrm{CoBr}}_2\right({\mathrm{NH}}_3{)}_2\left(\mathrm{en}\right){]}^{\oplus }$. Which one is wrong statement?

1. I and II are geometrical isomers 

2. II and III are optically active isomers 

3. I and III are optically active isomers

4.  II and III are geometrical isomers

A complex with the composition $[{\mathrm{MA}}_3\mathrm{B}{]}^{\mathrm{n}\pm }$ is found to have no geometrical isomers. The possible structures (s) of the complex is (Where A and B are monodentate ligands)

(1) Tetrahedral                   

(2) Square planar

(3) Both (a) and (b)             

(4) Cannot be predicted

Complexes formed in the following methods are:

(I) Mond's process for purification of nickel

(II) Removal of unreacted AgBr from photographic plate

(III) Removal of lead poisoning from the body

Options are as follows: 

$\mathrm{I} \mathrm{II} \mathrm{III}$
$\left(\mathrm{a}\right) \mathrm{Ni}(\mathrm{CO}{)}_{4 } [\mathrm{Ag}(\mathrm{CN}{)}_2{]}^{-} [\mathrm{Pb}\left(\mathrm{EDTA}\right){]}^{2-}$
$\left(\mathrm{b}\right) \mathrm{Ni}(\mathrm{CO}{)}_4 [\mathrm{Ag}({\mathrm{S}}_2{\mathrm{O}}_3{)}_2{]}^{3- } [\mathrm{Pb}\left(\mathrm{EDTA}\right){]}^{2-}$
$\left(\mathrm{c}\right) \mathrm{Ni}(\mathrm{CO}{)}_6 [\mathrm{Ag}\left({\mathrm{S}}_2{\mathrm{O}}_3\right){]}^{3-} \left[\mathrm{Pb}\right(\mathrm{EDTA}){]}^{4-}$
$\left(\mathrm{d}\right) \mathrm{Ni}(\mathrm{CO}{)}_6 [\mathrm{Ag}\left({\mathrm{S}}_2{\mathrm{O}}_3\right){]}^{-} \left[\mathrm{Pb}\right(\mathrm{EDTA}){]}^{4-}$
$$

The correct name for the complex ion $\left[\mathrm{CoCl}\right(\mathrm{ONO}\left)\right(\mathrm{en}{)}_2{]}^{+}$ is:

1. chlorobis(ethylenediamine)nitrito-O-cobaltate(III) ion

2. chlorodiethyldiaminenitrito-O-cobalt(III) ion

3. chloronitrito-O-diethyldiamine cobaltate (III) ion

4. chlorobis (ethylenediamine)nitrito-O-cobalt (III) ion

Which of the following ligand does not as $\mathrm{\pi }$-acid ligand?

(a) ${\mathrm{N}}_2$           (b) CO              (c) ${\mathrm{C}}_2{\mathrm{H}}_4$                 (d) ${\mathrm{O}}_2^{2-}$

$\left[\mathrm{Mn}\right(\mathrm{CO}{)}_4\mathrm{NO}]$ is diamagnetic because:

1. Mn metal is paramagnetic in free state

2. Mn is in +1 oxidation state in this complex

3. NO is present as positive ligand

4. All of the above