The instantaneous displacement of a simple pendulum oscillator is given by x=A cos ωt+π4 . Its speed will be maximum at time

1. π4ω      

2. π2ω

3. πω                

4. 2πω

Subtopic:  Simple Harmonic Motion |
 61%
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The displacement of a particle moving in S.H.M. at any instant is given by y=a sinωt . The acceleration after time t=T4 (where T is the time period) -

1. aω                         

2.-aω

3. aω2                         

4.  -aω2

 

Subtopic:  Simple Harmonic Motion |
 87%
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The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

1  144π2m/sec2       
2  144m/sec2

3. 144π2m/sec2          
4. 288π2m/sec2   

Subtopic:  Simple Harmonic Motion |
 88%
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A particle moving along the x-axis executes simple harmonic motion, then the force acting on it is given by

1.  – A Kx           

2.  A cos (Kx)

3.  A exp (– Kx

4.  A Kx

Subtopic:  Simple Harmonic Motion |
 84%
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What is the maximum acceleration of the particle doing the SHM y=2sinπt2+ϕ where 2 is in cm

1.  π2cm/s2                
2.  π22cm/s2
3.  π4cm/s2             
4.  π4cm/s2

Subtopic:  Simple Harmonic Motion |
 92%
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A particle executes simple harmonic motion along a straight line with an amplitude A. The potential energy is maximum when the displacement is

1.  ±A          

2.  Zero

3.  ±A2         

4.  ±A2

Subtopic:  Energy of SHM |
 81%
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The potential energy of a particle with displacement X depends as U(X). The motion is simple harmonic, when (K is a positive constant)

1. U=KX22                 

2. U=KX2   

3.  U=K                       

4. U=KX 

Subtopic:  Energy of SHM |
 81%
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The angular velocity and the amplitude of a simple pendulum is ω and a respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is 

1,  X2ω2a2-X2ω2       

2.  X2/a2-x2

3.  a2-X2ω2/X2ω2       

4. (a2-x2)/X2

Subtopic:  Energy of SHM |
 78%
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A particle is executing simple harmonic motion with frequency \(f\). The frequency at which its kinetic energy changes into potential energy, will be:
1. \(\frac{f}{2}\)
2. \(f\)
3. \(2f\)
4. \(4f\)
Subtopic:  Energy of SHM |
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There is a body having mass m and performing S.H.M. with amplitude a. There is a restoring force ,F=-Kx where x is the displacement. The total energy of body depends upon -

1.  K, x         

2.  K, a

3.  K, a, x    

4.  K, a, v

Subtopic:  Energy of SHM |
 72%
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