In the circuit shown in figure, each capacitor has a capacity of 3 μF. The equivalent capacity between A and B is 

(1) 34μF

(2) 3 μF

(3) 6 μF

(4) 5 μF

Subtopic:  Combination of Capacitors |
 57%
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Two capacitors A and B are connected in series with a battery as shown in the figure. When the switch S is closed and the two capacitors get charged fully, then 

1. The potential difference across the plates of A is 4V and across the plates of B is 6V

2. The potential difference across the plates of A is 6V and across the plates of B is 4V

3. The ratio of electrical energies stored in A and B is 2 : 3

4. The ratio of charges on A and B is 3 : 2

Subtopic:  Energy stored in Capacitor |
 78%
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In the figure, three capacitors each of capacitance 6 pF are connected in series. The total capacitance of the combination will be 

(1) 9 × 10–12 F

(2) 6 × 10–12 F

(3) 3 × 10–12 F

(4) 2 × 10–12 F

Subtopic:  Combination of Capacitors |
 88%
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Equivalent capacitance between A and B is 

1. 8 μF

2. 6 μF

3. 26 μF

4. 10/3 μF

Subtopic:  Combination of Capacitors |
 86%
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In the figure a capacitor is filled with dielectrics. The resultant capacitance is 

(1) 2ε0Ad1k1+1k2+1k3

(2) ε0Ad1k1+1k2+1k3

(3) 2ε0Ad[k1+k2+k3]

(4) None of these

Subtopic:  Combination of Capacitors |
 63%
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Three capacitors of capacitance 3 μF, 10 μF and 15 μF are connected in series to a voltage source of 100V. The charge on 15 μF is 

(1) 50 μC

(2) 100 μC

(3) 200 μC

(4.) 280 μC

Subtopic:  Combination of Capacitors |
 82%
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Two capacitors \(C_1 = 2~\mu\text{F}\) and \(C_2 = 6~\mu \text{F}\) in series, are connected in parallel to a third capacitor \(C_3= 4~\mu\text{F}\). This arrangement is then connected to a battery of \(\text{emf}= 2~\text{V}\), as shown in the figure. How much energy is lost by the battery in charging the capacitors? 


1. \(22\times 10^{-6}~\text{J}\)
2. \(11\times 10^{-6}~\text{J}\)
3. \(\frac{32}{3}\times 10^{-6}~\text{J}\)
4. \(\frac{16}{3}\times 10^{-6}~\text{J}\)

Subtopic:  Energy stored in Capacitor |
 78%
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A parallel plate capacitor has capacitance \(C\). If it is equally filled with parallel layers of materials of dielectric constants \(K_1\) and \(K_2\), its capacity becomes \(C_1\). The ratio of \(C_1\) to \(C\) is:

1. \(K_1 + K_2\) 2. \(\frac{K_{1} K_{2}}{K_{1}-K_{2}}\)
3. \(\frac{K_{1}+K_{2}}{K_{1} K_{2}}\) 4. \(\frac{2 K_{1} K_{2}}{K_{1}+K_{2}}\)
Subtopic:  Dielectrics in Capacitors |
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The equivalent capacitance in the circuit between A and B will be 

(1) 1 μF

(2) 2 μF

(3) 3 μF

(4) 13μF

Subtopic:  Combination of Capacitors |
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The equivalent capacitance between A and B is 

(1) C4

(2) 3C4

(3) C3

(4) 4C3

Subtopic:  Combination of Capacitors |
 78%
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