A liquid drop of diameter D breaks upto into 27 small drops of equal size. If the surface tension of the liquid is , then change in surface energy is
(a) (b)
(c) (d)
One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is
(1) 1000 : 1
(2) 1 : 1000
(3) 10 : 1
(4) 1 : 10
A big drop of radius R is formed by 1000 small droplets of water, then the radius of small drop is
(1) R/2
(2) R/5
(3) R/6
(4) R/10
8000 identical water drops are combined to form a big drop. Then the ratio of the final surface energy to the initial surface energy of all the drops together is
(1) 1 : 10
(2) 1 : 15
(3) 1 : 20
(4) 1 : 25
When two small bubbles join to form a bigger one, energy is
(1) Released
(2) Absorbed
(3) Both (1) and (2)
(4) None of these
A water film is formed between the two straight parallel wires, each of length \(10~\text{cm}\), kept at a separation of \(0.5~\text{cm}.\)Now, the separation between them is increased by \(1~\text{mm}\) without breaking the water film. The work done for this is
(surface tension of water =\(7.2\times 10^{-2}~\text{N/m}\))
1. \(7.22\times 10^{-6}~\text{J}\)
2. \(1.44\times 10^{-5}~\text{J}\)
3. \(2.88\times 10^{-5}~\text{J}\)
4. \(5.76\times 10^{-5}~\text{J}\)
A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. (Surface tension of mercury is )
(1)
(2)
(3)
(4)
Two small drops of mercury, each of radius r, coalesce to form a single large drop. The ratio of the total surface energies before and after the change is
1.
2.
3. 2:1
4. 1:2
If two soap bubbles of equal radii r coalesce then the radius of curvature of interface between two bubbles will be
(1) r
(2) 0
(3) Infinity
(4) 1/2r
The angle of contact between glass and mercury is
(1) 0°
(2) 30°
(3) 90°
(4) 135°