By inserting a capillary tube up to a depth l in water, the water rises to a height of h ( h<l). If the lower end of the capillary is closed inside the water and the capillary is taken out and closed-end opened, to what height the water will remain in the tube?

(1) Zero

(2) l+h 

(3) 2h

(4) h

A capillary tube when immersed vertically in liquid records a rise of 3 cm. If the tube is immersed in the liquid at an angle of $60°$ with the vertical. The length of the liquid column along the tube is 

(1) 9cm

(2) 6cm

(3) 3cm

(4) 2cm

The action of a nib split at the top is explained by

1. Gravity flow

2. Diffusion of fluid

3. Capillary action

4. Osmosis of liquid

The correct relation is

(1) $\mathrm{r}=\frac{2\mathrm{Tcos\theta }}{\mathrm{hdg}}$

(2) $\mathrm{r}=\frac{\mathrm{hdg}}{2\mathrm{Tcos\theta }}$

(3) $\mathrm{r}=\frac{2\mathrm{Tdgh}}{\mathrm{cos\theta }}$

(4) $\mathrm{r}=\frac{\mathrm{Tcos\theta }}{2\mathrm{hdg}}$

During the capillary rise of a liquid in a capillary tube, the surface of contact that remains constant is of

(1) Glass and liquid

(2) Air and glass

(3) Air and liquid

(4) All of these

A shell having a hole of radius r is dipped in water. It holds the water up to a depth of h then the value of r is

(1) $\mathrm{r}=\frac{2\mathrm{T}}{\mathrm{hdg}}$

(2) $\mathrm{r}=\frac{\mathrm{T}}{\mathrm{hdg}}$

(3) $\mathrm{r}=\frac{\mathrm{Tg}}{\mathrm{hd}}$

(4) None of these

If the capillary experiment is performed in a vacuum, then for a liquid there capillary rise 

(1) It will rise

(2) Will remain the same

(3) It will fall

(4) Rise to the top

If liquid level falls in a capillary then radius of capillary will

(1) Increase                     

(2) Decrease

(3) Unchanged                 

(4) None of these

Water rises to a height \(\mathrm{h}\) in a capillary at the surface of earth. On the surface of the moon, the height of water column in the same capillary will be:
1. \(\mathrm{6h}\)                           
2. $\frac{1}{6}\mathrm{h}$
3.  \(\mathrm{h}\)                             
4. \(\mathrm{zero}\)

Two capillary tubes of the same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 and 50 dyne/cm respectively Ratio of heights of liquids in the two tubes $\frac{{\mathrm{h}}_1}{{\mathrm{h}}_2}$ is

(1) $\frac{10}{9}$

(2) $\frac{3}{10}$

(3) $\frac{10}{3}$

(4) $\frac{9}{10}$