A compound contains atoms of three elements A,B and C. If the oxidation number of A is +2, Bis +5 and that of C is -2, the possible formula of the compound is : 

1. A₂(BC₃)₂
2. A₃(B₄C)₂
3. A₃(BC₄)₂
4. ABC₂ 

The number of peroxide linkages in CrO₅ is /are

1. One

2. Two

3. Three

4. None of the above

Conversion of PbSO₄ to PbS is:

1. Reduction of S

2. Oxidation of S

3. Dissociation

4. None of the above

Redox reaction among the following is -

1. NaCl + KNO₃ $\to$NaNO₃ + KCl

2. CaC₂O₄ + 2HCl $\to$CaCl₂ + H₂C₂O₄

3. Mg(OH)₂ + 2NH₄Cl $\to$MgCl₂ + 2NH₄OH

4. Zn + 2AgCN $\to$2Ag + Zn(CN)₂

The oxidation number of Fe in K₃[Fe(CN)₆] is-

1. +2

2. +3

3. +4

4. +1

It is found that v forms a double salt isomorphous with Mohr's salt. The oxidation number of V in this compound is:

1. +3

2. +2

3. +4

4. -4

The correct order of reducing power of halide ions is:

1. Cl^- > Br^- > I^- > F^-

2. Cl^- >  I^- > Br^- > F^-

3.  Br^- > Cl^- > I^- > F^-

4.  I^- > Br^- > Cl^- > F^-

The reaction during which nitrogen gets oxidised is-

1. ${\mathrm{NH}}_4^{+}$ $\to$N₂

2. ${\mathrm{NO}}_3^{-} \to$NO

3. NO₂ $\to$${\mathrm{NO}}_2^{-}$

4. ${\mathrm{NO}}_3^{-}$$\to$N${\mathrm{H}}_4^{+}$ 

Reaction that shows hydrogen as an oxidising agent is:

1. With iodine to give hydrogen iodide

2. With lithium to give lithium hydride

3. With nitrogen to give ammonia

4. With sulphur to give hydrogen sulphide

Fluorine is a strong oxidising agent because:

1. it has several isotopes

2. it is very small and has 7 electrons in valency shell

3. its valency is one

4. it is the first member of the halogen series