In the given progressive wave equation, what is the maximum velocity of particle $Y=0.5\sin (10\pi t-5x)$cm 

(1) 5 cm/s

(2) 5π cm/s

(3) 10 cm/s

(4) 10.5 cm/s

Two waves of frequencies 20 Hz and 30 Hz travel out from a common point. The phase difference between them after 0.6 sec is :

(1) Zero

(2) $\frac{\pi }{2}$

(3) π

(4) $\frac{3\pi }{4}$

A simple harmonic progressive wave is represented by the equation : $y=8\sin 2\pi (0.1x-2t)$ where x and y are in cm and t is in seconds. At any instant the phase difference between two particles separated by 2.0 cm in the x-direction is :

(1) 18°

(2) 36°

(3) 54°

(4) 72°

The equation of progressive wave is $y=a\sin (200t-x)$. where x is in meter and t is in second. The velocity of wave is :

(1) 200 m/sec

(2) 100 m/sec

(3) 50 m/sec

(4) None of these

A wave equation that gives the displacement along y-direction is given by $y=0.001\sin (100t+x)$ where x and y are in meter and t is time in seconds. This represented a wave :

(1) Of frequency $\frac{100}{\pi }$Hz

(2) Of wavelength one metre

(3) Traveling with a velocity of $\frac{50}{\pi }$ms^–1 in the positive X-direction

(4) Traveling with a velocity of 100 ms^–1 in the negative X-direction

A wave travelling in positive X-direction with A = 0.2 m has a velocity of 360 m/sec. if λ = 60 m, then the correct expression for the wave is :

(1) $y=0.2\sin \left[2\pi \left(6t+\frac{{\displaystyle x}}{{\displaystyle 60}}\right)\right]$

(2) $y=0.2\sin \left[\pi \left(6t+\frac{{\displaystyle x}}{{\displaystyle 60}}\right)\right]$

(3) $y=0.2\sin \left[2\pi \left(6t-\frac{{\displaystyle x}}{{\displaystyle 60}}\right)\right]$

(4) $y=0.2\sin \left[\pi \left(6t-\frac{{\displaystyle x}}{{\displaystyle 60}}\right)\right]$

Two waves represented by the following equations are travelling in the same medium $y_1=5\sin 2\pi (75t-0.25x)$, $y_2=10\sin \pi (150t-0.50x)$

The intensity ratio I₁/I₂ of the two waves is :

(1) 1 : 2

(2) 1 : 4

(3) 1 : 8

(4) 1 : 16

Which of the following is not true for this progressive wave $y=4\sin 2\pi \left(\frac{{\displaystyle t}}{{\displaystyle 0.02}}-\frac{{\displaystyle x}}{{\displaystyle 100}}\right)$ where y and x are in cm and t in sec 

(1) Its amplitude is 4 cm

(2) Its wavelength is 100 cm

(3) Its frequency is 50 cycles/sec

(4) Its propagation velocity is 50 × 10³ cm/sec

A transverse progressive wave on a stretched string has a velocity of 10 ms^–1 and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be :

(1) $\frac{\pi }{8}$

(2) $\frac{\pi }{4}$

(3) $\frac{3\pi }{8}$

(4) $\frac{\pi }{2}$

The phase difference between two waves represented by $y_1={10}^{-6}\sin [100t+(x/50)+0.5]m,$ $y_2={10}^{-6}\cos [100t+(x/50\left)\right]m$ where x is expressed in metres and t is expressed in seconds, is approximately:

(1) 1.5 rad

(2) 1.07 rad

(3) 2.07 rad

(4) 0.5 rad