Two tuning forks when sounded together produced 4 beats/sec. The frequency of one fork is 256 Hz. The number of beats heard increases when the fork of frequency 256 Hz is loaded with wax. The frequency of the other fork is(in Hz) :

(1) 504

(2) 520

(3) 260

(4) 252

Subtopic:  Beats |
 65%
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Tuning fork \(F_1\) has a frequency of \(256~\text{Hz}\) and it is observed to produce \(6\) beats/second with another tuning fork \(F_2\). When \(F_2\) is loaded with wax, it still produces \(6\) beats/second with \(F_1\). The frequency of \(F_2\) before loading was:
1. \(253~\text{Hz}\)
2. \(262~\text{Hz}\)
3. \(250~\text{Hz}\)
4. \(259~\text{Hz}\)
Subtopic:  Beats |
 71%
From NCERT
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Beats are produced by two waves given by y1=asin2000πt and y2=asin2008πt. The number of beats heard per second is :

(1) Zero

(2) One

(3) Four

(4) Eight

Subtopic:  Beats |
 83%
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The distance between the nearest node and antinode in a stationary wave is :

(1) λ

(2) λ2

(3) λ4

(4) 2λ

Subtopic:  Standing Waves |
 83%
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For the stationary wave y=4sinπx15cos(96πt), the distance between a node and the next antinode is :

1. 7.5

2. 15

3. 22.5

4. 30

Subtopic:  Standing Waves |
 75%
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The equation of a stationary wave is \(y = 0.8\cos\left(\frac{\pi x}{20}\right)\sin200(\pi t)\), where \(x\) is in \(\text{cm}\) and \(t\) is in \(\text{sec}.\) The separation between consecutive nodes will be:
1. \(20~\text{cm}\)
2. \(10~\text{cm}\)
3. \(40~\text{cm}\)
4. \(30~\text{cm}\)
Subtopic:  Standing Waves |
 78%
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A wave represented by the given equation y=acos(kxωt) is superposed with another wave to form a stationary wave such that the point x = 0 is a node. The equation for the other wave is :

(1) y=asin(kx+ωt)

(2) y=acos(kx+ωt)

(3) y=acos(kxωt)

(4) y=asin(kxωt)

Subtopic:  Standing Waves |
 56%
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A standing wave is represented by

Y=Asin(100t)cos(0.01x)

where Y and A are in millimetre, t is in seconds and x is in metre. The velocity of the wave is :

(1) 104 m/s

(2) 1 m/s

(3) 10–4 m/s

(4) Not derivable from the above data

Subtopic:  Standing Waves |
 84%
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A 1 cm long string vibrates with the fundamental frequency of 256 Hz. If the length is reduced to 14cm  keeping the tension unaltered, the new fundamental frequency will be :

(1) 64

(2) 256

(3) 512

(4) 1024

Subtopic:  Travelling Wave on String |
 72%
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The tension in a piano wire is 10N. What should be the tension in the wire to produce a note of double the frequency :

(1) 5 N

(2) 20 N

(3) 40 N

(4) 80 N

Subtopic:  Travelling Wave on String |
 85%
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