The diode used in the circuit shown in the figure has a constant voltage drop of \(0.5~\text{V}\) at all currents and a maximum power rating of \(100\) milliwatts. What should be the value of the resistor \(R\), connected in series with the diode for obtaining maximum current?


1. \(1.5~\Omega\)
2. \(5~\Omega\)
3. \(6.67~\Omega\)
4. \(200~\Omega\)

Subtopic:  PN junction |
 62%
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For a transistor amplifier in common emitter configuration for load impedance of 1 kΩ (hfe = 50 and hoe = 25 μA/V) the current gain is 

(a) – 5.2                   (b) – 15.7

(c) – 24.8                  (d) – 48.78

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In the following common emitter configuration an NPN transistor with current gain β = 100 is used. The output voltage of the amplifier will be 

(1) 10 mV

(2) 0.1 V

(3) 1.0 V

(4) 10 V

Subtopic:  Transistor (OLD NCERT) |
 67%
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A sinusoidal voltage of peak value 200 volts is connected to a diode and resistor R in the circuit shown so that half-wave rectification occurs. If the forward resistance of the diode is negligible compared to R the r.m.s voltage (in volt) across R is approximately

(1) 200                           

(2) 100

(3) 2002                         

(4) 280

Subtopic:  PN junction |
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The junction diode in the following circuit requires a minimum current of 1 mA to be above the knee point (0.7 V) of its I-V characteristic curve. The voltage across the diode is independent of current above the knee point. If VB = 5 V, then the maximum value of R so that the voltage is above the knee point, will be

(1) 4.3 kΩ                

(2) 860 kΩ

(3) 4.3 Ω                  

(4) 860 Ω

Subtopic:  PN junction |
 80%
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In the circuit given below, V(t) is the sinusoidal voltage source, voltage drop VAB(t) across the resistance R is

(1) Is half wave rectified

(2) Is full wave rectified

(3) Has the same peak value in the positive and negative half cycles

(4) Has different peak values during positive and negative half cycle

Subtopic:  Applications of PN junction |
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The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is 10 V. The dc component of the output voltage is 
(1)10/2  V                                   

(2) 10/π V

(3) 10 V                                           

(4) 20/π V

Subtopic:  Rectifier |
 55%
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A transistor is used as an amplifier in CB mode with a load resistance of 5 kΩ. The current gain of the amplifier is 0.98 and the input resistance is 70 Ω, the voltage gain and power gain respectively are :
(1) 70, 68.6                         

(2) 80, 75.6

(3) 60, 66.6                         

(4) 90, 96.6

Subtopic:  Applications of Transistor (OLD NCERT) |
 78%
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The Bohr radius of the fifth electron of phosphorus (atomic number = 15) acting as dopant in silicon (relative dielectric constant = 12) is
(a) 10.6 Å                (b) 0.53 Å
(c) 21.2 Å                (d) None of these

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In the following circuits PN-junction diodes D1D2 and D3 are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will be

(i) – 10 V, – 5V           (ii) – 5V, – 10 V
(iii) – 4V, – 12V

(a) (i) < (ii) < (iii)                       (b) (iii) < (ii) < (i)
(c) (ii) = (iii) < (i)                       (d) (i) = (iii) < (ii)

Subtopic:  Applications of PN junction |
 63%
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