In a closed organ pipe, the frequency of the fundamental note is 50 Hz. The note of which of the following frequencies will not be emitted by it :

(1) 50 Hz

(2) 100 Hz

(3) 150 Hz

(4) None of the above

On producing the waves of frequency 1000 Hz in a Kundt's tube, the total distance between 6 successive nodes is 85 cm. Speed of sound in the gas filled in the tube is 

(1) 330 m/s

(2) 340 m/s

(3) 350 m/s

(4) 300 m/s

What is the base frequency if a pipe gives notes of frequencies 425, 255 and 595 and decide whether it is closed at one end or open at both ends :

(1) 17, closed

(2) 85, closed

(3) 17, open

(4) 85, open

A student determines the velocity of sound with the help of a closed organ pipe. If the observed length for fundamental frequency is \(24.7~\text{cm}\), the length for third harmonic will be:
1. \(74.1~\text{cm}\)
2. \(72.7~\text{cm}\)
3. \(75.4~\text{cm}\)
4. \(73.1~\text{cm}\)

In a resonance tube the first resonance with a tuning fork occurs at 16 cm and second at 49 cm. If the velocity of sound is 330 m/s, the frequency of tuning fork is :

(1) 500

(2) 300

(3) 330

(4) 165

Two closed organ pipes of length 100 cm and 101 cm 16 beats in 20 sec. When each pipe is sounded in its fundamental mode calculate the velocity of sound 

(1) 303 ms^–1

(2) 332 ms^–1

(3) 323.2 ms^–1

(4) 300 ms^–1

An organ pipe, open from both end produces 5 beats per second when vibrated with a source of frequency 200 Hz. The second harmonic of the same pipe produces 10 beats per second with a source of frequency 420 Hz. The frequency of source is 

(1) 195 Hz

(2) 205 Hz

(3) 190 Hz

(4) 210 Hz

In one metre long open pipe what is the harmonic of resonance obtained with a tuning fork of frequency 480 Hz : (Velocity of sound: 320 m/s)

(1) First

(2) Second

(3) Third

(4) Fourth

In a resonance pipe the first and second resonances are obtained at depths 22.7 cm and 70.2 cm respectively. What will be the end correction 

(1) 1.05 cm

(2) 115.5 cm

(3) 92.5 cm

(4) 113.5 cm

An open tube is in resonance with string (frequency of vibration of the tube is n₀). If the tube is dipped in water so that 75% of the length of the tube is inside water, then the ratio of the frequency of tube to string now will be :

(1) 1

(2) 2

(3) $\frac{2}{3}$

(4) $\frac{3}{2}$