What is the momentum of a photon in an \(X\text-\)ray beam of \(10^{-10}\) meter wavelength?

1.	\(1.5 \times 10^{-23}~\text{kg-m/s}\)
2.	\(6.6 \times 10^{-24}~\text{kg-m/s}\)
3.	\(6.6 \times 10^{-44}~\text{kg-m/s}\)
4.	\(2.2 \times 10^{-52}~\text{kg-m/s}\)

The energy of a photon of light with wavelength 5000 Å is approximately 2.5 eV. This way the energy of an X-ray photon with wavelength 1Å would be 
(1) 2.5/5000 eV             

(2) $2.5/{\left(5000\right)}^2 \mathrm{eV}$

(3) $2.5\times 5000 \mathrm{eV}$           

(4)  $2.5\times {\left(5000\right)}^2 \mathrm{eV}$

Wavelength of a 1 keV photon is $1.24\times {10}^{-9}m$. What is the frequency of 1 MeV photon?

1. $1.24\times {10}^{15} \mathrm{Hz}$      
2.  $2.4\times {10}^{20} \mathrm{Hz}$
3. $1.24\times {10}^{18} \mathrm{Hz}$      
4. $2.4\times {10}^{23} \mathrm{Hz}$

What is the momentum of a photon having frequency $1.5\times {10}^{13} \mathrm{Hz}$?
(a) $3.3\times {10}^{-29} \mathrm{kg} \mathrm{m}/\mathrm{s}$                (b) $3.3\times {10}^{-34} \mathrm{kg} \mathrm{m}/\mathrm{s}$
(c) $6.6\times {10}^{-34} \mathrm{kg} \mathrm{m}/\mathrm{s}$                (d) $6.6\times {10}^{-30} \mathrm{kg} \mathrm{m}/\mathrm{s}$

The energy of a photon of light of wavelength 450 nm is

(1) $4.4\times {10}^{-19} \mathrm{J}$             

(2) $2.5\times {10}^{-19} \mathrm{J}$

(3) $1.25\times {10}^{-17} \mathrm{J}$            

(4) $2.5\times {10}^{-17} \mathrm{J}$

Which of the following is true for photon 
(1) $\mathrm{E}=\frac{\mathrm{hc}}{\mathrm{\lambda }}$         

(2) $\mathrm{E}=\frac{1}{2}{\mathrm{mu}}^2$

(3) $\mathrm{p}=\frac{\mathrm{E}}{2\mathrm{v}}$         

(4) $\mathrm{E}=\frac{1}{2}{\mathrm{mc}}^2$

Which of the following is incorrect statement regarding photon: 

(1) Photon exerts no pressure

(2) Photon energy is hv

(3) Photon rest mass is zero

(4) None of these

There are ${\mathrm{n}}_1$ photons of frequency ${\mathrm{\gamma }}_1$ in a beam of light. In an equally energetic beam, there are ${\mathrm{n}}_2$ photons of frequency ${\mathrm{\gamma }}_2$ . Then the correct relation is -
1. $\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=1$                       

2.  $\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{{\mathrm{\gamma }}_1}{{\mathrm{\gamma }}_2}$
3.  $\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{{\mathrm{\gamma }}_2}{{\mathrm{\gamma }}_1}$                     

4.  $\frac{{\mathrm{n}}_1}{{\mathrm{n}}_2}=\frac{{\mathrm{\gamma }}_1^2}{{\mathrm{\gamma }}_2^2}$

Einstein's photoelectric equation states that \(E_k=h \nu -\phi.\)${\mathrm{}}_{}$ In this equation \(E_k\) refers to: