The products of the electrolysis of aqueous solution of common salt are:

1. Na + Cl2

2. H2 + O2

3. NaOH + H2 + Cl2

4. NaOH + Cl2 + O2

Subtopic:  Physical Properties | Preparations, Properties & Uses of S Block Elements |
 73%
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Sodium cannot be extracted by the electrolysis of brine solution because:

1. sodium leberated reacts with water to produce NaOH+H2

2. sodium being more electropositive than hydrogen, H2 is liberated at cathod and not sodium

3. electrolysis cannot take place with brine solution

4. none of the above

Subtopic:  Chemical Properties |
 62%
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KO2 is used in oxygen cylinder in space air craft and submarines because it:

1. absorbs CO2 and increase O2 content

2. eliminate moisture

3. absorbs CO2

4. produces O2

Subtopic:  Physical Properties | Chemical Properties |
 68%
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Tin dissolves in boiling caustic soda solution because of the formation of soluble:

1. Sn(OH)2

2. Sn(OH)4

3. Na2SnO3

4. none of these

Subtopic:  Preparations, Properties & Uses of S Block Elements |
 51%
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Potash alum is used in purification of water because:

1. it kills the micro-organisms

2. it precipitates the colloidal matter

3. it removes the hardness of water

4. it catalyses the removal of impurities

Subtopic:  Chemical Properties |
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The pair of compounds which cannot exist together in solution is:

1. NaHCO3 and NaOH

2. Na2CO3 and NaHCO3

3. Na2CO3 and NaOH

4. NaHCO3 and NaCl

Subtopic:  Chemical Properties |
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Which one is the highest melting point halide?

1. NaCl

2. NaBr

3. NaF

4. NaI

Subtopic:  Physical Properties | Preparations, Properties & Uses of S Block Elements |
 66%
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LiAlH4 is obtained by reacting an excess of ...... with an etheral solution of AlCl3.

1. LiCl

2. LiH

3. Li

4. LiOH

Subtopic:  Chemical Properties |
 61%
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Manufacture of NaOH is done by:

1. Castner - Kellner process

2. Solvay process

3. Brine process

4. Mond's process

Subtopic:  Preparations, Properties & Uses of S Block Elements |
 75%
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Sodium does not form Na2+ ,because:

1. Sodium contains only one electron in its outermost shell

2. First ionization potential is small and the difference in first and second ionization potential is very large.

3. Radius of Na+2 is much smaller than of Na+

4. None of the above.

Subtopic:  Physical Properties |
 64%
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