Among acetic acid, phenol and n-hexanol which one of the following compound will react with NaHCO₃ solution to give sodium salt and CO₂?                                             

1. Acetic acid

2. n-Hexanol

3. Acetic acid and Phenol

4. Phenol

The compound that does not yield a positive result in the iodoform test is:

1. 2-Pentanone                 

2. Ethanol

3. Ethanal                         

4. 3-Pentanone

Two isomeric ketones 3-Pentanones and 2-Pentanone can be distinguished by:

1. I₂/NaOH only               

2. NaHSO₃ only

3. NaCN/HCl                     

4. Both of (a) and (b)   

Products of the following reaction                                   

  CH₃C$\equiv$C-CH₂CH₃ $\underset{\left(\mathrm{ii}\right) \mathrm{hydrolysis}}{\overset{\left(\mathrm{i}\right) {\mathrm{O}}_3}{\to }}$ ... are

1. CH₃CHO + CH₃CH₂CHO

2. CH₃COOH + CH₃COCH₃

3. CH₃COOH + HOOC-CH₂CH₃

4. CH₃COOH + CO₂

Which alkene on ozonolysis gives CH₃CH₂CHO and CH₃COCH₃?                                          

1. CH₃CH₂CH=C${<}_{{\mathrm{CH}}_3}^{{\mathrm{CH}}_3}$

2. CH₃CH₂CH=CHCH₂CH₃

3. CH₃CH₂CH=CHCH₃

4. ${\mathrm{CH}}_3-\underset{|}{\mathrm{C}}={\mathrm{CHCH}}_3$
${\mathrm{CH}}_3$

Benzoic acid gives benzene on being heated with X and phenol gives benzene on being heated with Y. Therefore, X and Y are respectively                                                              

1. Sodalime and copper

2. Zn dust and NaOH

3. Cu and sodalime

4. Sodalime and zinc dust

Which one of the following on oxidation gives a ketone?                       

1. primary alcohol                     

2. secondary alcohol

3. tertiary alcohol                     

4. All of these

A carbonyl compound reacts with hydrogen cyanide to form cyanohydrin which on hydrolysis forms a racemic mixture of $\mathrm{\alpha }$-hydroxy acid. The carbonyl compound is

1. acetaldehyde 

2. acetone

3. diethyl ketone 

4. formaldehyde                              

Consider the following transformations

CH₃COOH $\stackrel{{\mathrm{CaCO}}_3}{\to }$A$\stackrel{\mathrm{heat}}{\to }$B$\underset{\mathrm{NaOH}}{\overset{{\mathrm{I}}_2}{\to }}$C The molecular formula of C is                       

1. ${\mathrm{CH}}_3-\underset{\mathrm{I}}{\overset{\mathrm{OH}}{\underset{\left|}{\overset{\right|}{\mathrm{C}}}}}-{\mathrm{CH}}_3$

2. ${\mathrm{ICH}}_2-{\mathrm{COCH}}_3$

3. ${\mathrm{CHI}}_3$

4. ${\mathrm{CH}}_3\mathrm{I}$

The product formed in aldol condensation is                                                                 

1. a beta-hydroxy acid

2. a beta-hydroxy aldehyde or a beta-hydroxy ketone

3. an alpha-hydroxy aldehyde or ketone

4. an alpha, beta unsaturated ester