In the following reaction,

Product A is-

1. 

2. 

3. 

4. 

CH₃-C$\equiv$C-H$\stackrel{{\mathrm{CH}}_3\mathrm{MgBr}}{\to }$CH₄ + (A)$\underset{\left(\mathrm{ii}\right) {\mathrm{H}}_2\mathrm{O}/{\mathrm{H}}^{+}}{\overset{\left(\mathrm{i}\right) {\mathrm{CO}}_2}{\to }}$(B); (B) is -

1. H₃C-CH₂-CH₂-COOH

2. CH₃-C$\equiv$C-CH₃

3. H₃C-C$\equiv$C-COOH

4. H₃C-CH=CH-COOH

3-Hexyne can be converted to trans-3-Hexene by the action of:

1. ${\mathrm{H}}_2$ - Pd/ ${\mathrm{BaSO}}_4$                       

2. Li-Liq. ${\mathrm{NH}}_3$

3. ${\mathrm{H}}_2$ - Pt ${\mathrm{O}}_2$                               

4. ${\mathrm{NaBH}}_4$

A compound having the shortest carbon-carbon bond length among the following is :

1. Benzene                                 

2. Ethene

3. Ethyne                                   

4. Ethane

Reaction of HBr with propene in the presence of peroxide gives

1. iso-propyl bromide

2. 3-bromo propane

3. allyl bromide

4. n-propyl bromide

In the reaction, ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_3\stackrel{\mathrm{Oxidation}}{\to }$A $\stackrel{\mathrm{NaOH}}{\to }$B$\underset{∆}{\overset{\mathrm{Soda} \mathrm{lime}}{\to }}$C 

the product C is:

1. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{OH}$ 

2. ${\mathrm{C}}_6{\mathrm{H}}_6$

3. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{COONa}$

4. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{ONa}$

The compound formed when acetylene is passed through dilute sulphuric acid in the presence of mercury(II) sulphate is:

1. Ether

2. Ketone

3. Acetic acid

4. Acetaldehyde

Why are acetylenic hydrogens acidic?

A compound is treated with ${\mathrm{NaNH}}_2$ to give sodium salt. Identify the compound.

1. ${\mathrm{C}}_2{\mathrm{H}}_2$ 

2. ${\mathrm{C}}_6{\mathrm{H}}_6$

3. ${\mathrm{C}}_2{\mathrm{H}}_6$ 

4. ${\mathrm{C}}_2{\mathrm{H}}_4$

Which alkene on ozonolysis gives ${}_{}$
 \(CH_3CH_2CHO\) and  \(CH_3CCH_3\\ ~~~~~~~~||\\ ~~~~~~~~O\) 

1.

2. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CHCH}}_2{\mathrm{CH}}_3$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CHCH}}_3$

4.