The relation between velocity of two block \(v_1\) and \(v_2\) as shown in the figure is given by:

1. \(7v_1-v_2=0\)
2. \(7v_1+v_2=0\)
3. \(v_1+v_2=0\)
4. \(v_1+3v_2=0\)

Using constraint equations relation between $a_1$ and $a_2$ will be 

1. $a_1$ =3$a_2$

2. a$a_2$ =3$a_1$

3. a$a_2$= 6$a_1$

4. a$a_2$= 7$a_1$

A block of mass 2 kg is hanging with two identical massless springs as shown in  figure. The acceleration of the block just at the moment, the right spring breaks is (g = 10 $m/s^2$)

1. 10 $m/s^2$

2. 25 $m/s^2$

3. 5 $m/s^2$

4. 4 $m/s^2$

A piece of wire is bent in the shape of a parabola y = $k{x}^2$ (y-axis vertical) with a

bead of mass m on it. The bead can slide on the wire without friction. It stays at the lowest point of the parabola when the wire is at rest. The wire is now  accelerated parallel to the x-axis with a constant acceleration a. The distance of the new equilibrium position of the bead, where the bead can stay at rest with respect to the wire, from the y-axis is

1. $\frac{a}{gk}$

2. $\frac{a}{2gk}$

3. $\frac{2a}{gk}$

4. $\frac{a}{4gk}$

Three block of masses m, M and M’ are arranged as shown in fig. The surfaces are frictionless, pulley and strings are ideal. The mass M’ of the hanging block which will prevent the smaller block (m) from slipping over the wedge will be 

1. $\frac{M+m}{cot\theta -1}$

2. $\frac{M-m}{cot\theta -1}$

3. $\frac{M+m}{cot\theta +1}$

4. $\frac{M-m}{M+m}\tan \theta$

Two blocks of masses 2 $m$ and $m$ are connected as shown in the figure. Now the string between the blocks is suddenly cut. Then, at that instant, accelerations of the blocks A and B will be 

1. g and g, respectively

2. g and g/2, respectively

3. g/2 and g, respectively

4. g/2 and g/2, respectively

A block of mass $m$ is placed on the floor of lift which is moving with velocity $v$ = $4t^2$, where $t$ is time in second and velocity  m/s. Find the time at which normal force on the block is three times of its weight.

1. (3g/8)s

2. g s

3. g/4 s

4. 3g s

In the arrangement shown, the ends \(P\) and \(Q\) of an inextensible string move downwards with uniform speed \(v.\) The pulleys \(A\) and \(B\) are fixed. The mass \(M\) moves upward with a speed of:

    
1. \(2 v \cos \theta\)
2. \(v \cos \theta\)
3. \(\left(\frac{2 v}{\cos \theta}\right)\)
4. \(\left(\frac{v}{\cos \theta}\right)\)

A pendulum bob is suspended in a Car moving horizontally with acceleration ‘a’ the angle the string will make with vertical is

1. ${\tan }^{-1}\frac{g}{a}$

2. ${\tan }^{-1}\frac{a}{g}$

3. $si{n}^{-1}\frac{a}{g}$

4. ${\cos }^{-1}\frac{a}{g}$

A string with constant tension T is deflected through an angle $2{\theta }_0$ by a smooth fixed pulley. The force on the pulley is

$\left(\mathrm{a}\right) 2\mathrm{T} {\mathrm{cos\theta }}_0$
$\left(\mathrm{b}\right) \mathrm{T} {\mathrm{cos\theta }}_0$
$\left(\mathrm{c}\right) 2\mathrm{T} {\mathrm{sin\theta }}_0$
$\left(\mathrm{d}\right) \mathrm{T} {\mathrm{sin\theta }}_0$