Which of the following compounds decomposes on heating similar to $LiN{O}_3$.

(1) $Ba{\left(N{O}_3\right)}_2$                               

(2) $Sr{\left(N{O}_3\right)}_2$

(3) $Mg{\left(N{O}_3\right)}_2$                               

(4) All

Solubility of sulphates in water decreases from $MgS{O}_4$ to $BaS{O}_4$. It is due to the fact that –

(1) Ionic nature increases

(2) Size of $M^{2+}$ ion increases

(3) Lattice energy decrease

(4) Hydration enthalpy of $M^{2+}$ ions decreases

In the Solvay process of manufacture of sodium carbonate, the raw materials used are :

1. Aqueous NaOH, $N{H}_3$ and $C{O}_2$

2. Molten NaOH, $N{H}_3$ and CO

3. Brine NaCl, $N{H}_3$ and CO

4. Brine NaCl, $N{H}_3$ and $C{O}_2$

A blue coluored solution of an alkali metal in liq NH₃ is due to the presence of -

1. ${\mathrm{M}}^{-}$atoms.                                         

2. ${\mathrm{M}}^{+}$ ions .

3. Solvated anions  .                           

4. Solvated electrons.

Alkali metal ions are- 

1. Diamagnetic and coloured.

2. Diamagnetic and colourless.

3. Paramagnetic and coloured.

4. Paramagnetic and colourless.

A compound X on heating gives a colourless gas. The residue is dissolved in water to obtain Y. Excess $C{O}_2$ is bubbled through an aqueous solution of Y, and Z is formed. Z on gentle heating gives back X. The compound X is-

1. ${\mathrm{CaCO}}_3$                                           

2. ${\mathrm{Na}}_2{\mathrm{CO}}_3$

3. ${\mathrm{CaSO}}_4.2{\mathrm{H}}_2\mathrm{O}$                                 

4. ${\mathrm{K}}_2{\mathrm{CO}}_3$

Magnesia can be prepared by -

1. Burning Mg in air.

2. Heating hydroxide, nitrate, sulphate or carbonate of magnesium.

3. Heating Mg in steam.

4. All of the above.

A compound insoluble in acetic acid is  -

1. Calcium oxide.                    

2. Calcium carbonate.

3. Calcium oxalate.                      

4. Calcium hydroxide.

Assertion :  LiF is almost insoluble in water

Reason :  LiCl is soluble not only in water but also in acetone.

Assertion : s-block elements do not occur free in nature

Reason:  s-block elements are highly electropositive in nature.

1. Both A and R are true and R is the correct explanation of A.

2. Both A and R are true, but R is not the correct explanation of A.

3. A is true, but R is false.

4. Both A and R are false.