When vinyl chloride is passed through alcoholic KOH solution:

1. it dissolves                                 

2. it forms vinyl alcohol

3. it forms acetylene                     

4. it has no action

In the following reaction sequence, what is the final product, compound 'Z'?

1.	mixture of
2.
3.
4.

The reaction, RCl +NaI $\stackrel{\mathrm{Acetone}}{\to }\mathrm{R}-\mathrm{I}$ + NaCl is known as:

1. Wurtz reaction                     

 2. Fittig reaction                       

3. Frankland's reaction             

 4. Finkelstein's reaction                               

Elimination of HBr from 2-bromobutane results in the formation of:

1. equimolar mixture of 1- and 2-butene

2. predominantly 2-butene

3. predominantly 1-butene

4. predominantly 2-butyne

When (CH₃)₃CMgCl reacts with D₂O, it produces:

Benzoyl Chloride is prepared from benzoic acid by:

1. Cl₂, hv

2. SO₂Cl₂

3. SOCl₂

4. Cl₂, H₂O

In the following sequences of reactions;

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Br}\stackrel{\mathrm{KOH}(\mathrm{alc}.)}{\to }$(A)$\stackrel{\mathrm{HBr}}{\to }$(B)$\stackrel{\mathrm{KOH}\left(\mathrm{aq}\right)}{\to }$ (C)

the product (C) is:

1. propene                               

2. propyne

3. propan-1-ol                         

4. propan-2-ol

Iodoform can be prepared from all except :

1. Isopropyl alcohol

2. 3-methyl-2-butanone

3. isobutyl alcohol

4. ethyl methyl ketone

Which alkyl halide can't produce a white precipitate when combined with an alcoholic AgNO₃ solution?

1. Ethyl chloride                     

2. Allyl chloride

3. Isopropyl chloride               

4. Vinyl chloride

Identify (Z) in the following reaction reaction series,

C₂H₅I $\underset{\mathrm{KOH}}{\overset{\mathrm{Alcoholic}}{\to }}$(X) $\underset{}{\overset{{\mathrm{Br}}_2}{\to }}$(Y) $\stackrel{\mathrm{excess} \mathrm{KCN}}{\to }$(Z):

1. CH₃-CH₂-CN     

2. $\underset{\mathrm{CN}}{\underset{|}{{\mathrm{CH}}_2}}-\underset{\mathrm{CN}}{\underset{|}{{\mathrm{CH}}_2}}$

3. $\underset{Br}{\underset{|}{{\mathrm{CH}}_2}}-\underset{\mathrm{CN}}{\underset{|}{{\mathrm{CH}}_2}}$     

4. $\underset{\mathrm{CN}}{\underset{|}{\mathrm{CH}}}=\underset{\mathrm{CN}}{\underset{|}{\mathrm{CH}}}$