The large scale destruction, that would be caused due to the use of nuclear weapons is called 

(1) Nuclear holocaust

(2) Thermo-nuclear reaction

(3) Nuetron reproduction factor

(4) None of these

A radioactive substance has a half-life of 1 year. The fraction of this material, that would remain after 5 years will be

(1) $\frac{1}{32}$             

(2) $\frac{1}{5}$
(3) $\frac{1}{2}$               

(4) $\frac{4}{5}$

If half-life of a substance is 3.8 days and its quantity is 10.38 gm. Then substance quantity remaining left after 19 days will be 

(1) 0.151 gm             

(2) 0.32 gm

(3) 1.51 gm               

(4) 0.16 gm

Which is the correct expression for half-life

(1) ${\mathrm{t}}_{1/2}=\log 2$                 

(2) ${\mathrm{t}}_{1/2}=\frac{\mathrm{\lambda }}{\log 2}$
(3) ${\mathrm{t}}_{1/2}=\frac{\mathrm{\lambda }}{\log 2}(2.303)$     

(4) ${\mathrm{t}}_{1/2}=\frac{2.303 \log 2}{\mathrm{\lambda }}$

A nucleus ${}_{\mathrm{Z}}{}^{\mathrm{A}}\mathrm{A}$ emits an $\mathrm{\alpha }$-particle. The resultant nucleus emits a ${\mathrm{\beta }}^{+}$ particle. The respective atomic and mass no. of the final nucleus will be 

1. Z – 3, A – 4           

2. Z – 1, A – 4

3. Z – 2, A – 4           

4. Z, A – 2

The activity of a radioactive sample is 1.6 curie and its half-life is 2.5 days. Its activity after 10 days will be

(1) 0.8 curie       

(2) 0.4 curie

(3) 0.1 curie       

(4) 0.16 curie

In a mean life of a radioactive sample 

(1) About 1/3 of substance disintegrates

(2) About 2/3 of the substance disintegrates

(3) About 90% of the substance disintegrates

(4) Almost all the substance disintegrates

Three fourth of the active decays in a radioactive sample in 3/4 sec. The half life of the sample is 
(1) $\frac{1}{2}$ sec           

(2) 1 sec
(3) $\frac{3}{8}$ sec           

(4) $\frac{3}{4}$ sec

During mean life of a radioactive element, the fraction that disintegrates is:

(1) e           

(2)  $\frac{1}{\mathrm{e}}$
(3) $\frac{\mathrm{e}-1}{\mathrm{e}}$     

(4) $\frac{\mathrm{e}}{\mathrm{e}-1}$

1 Curie is equal to 

(1) $3\times {10}^{10}$ disintegrations/sec

(2) $3.7\times {10}^7$ disintegrations/sec

(3) $5\times {10}^7$ disintegrations/sec

(4) $3.7\times {10}^{10}$ disintegrations/sec