Formaldehyde can be distinguished from acetaldehyde by:

1. Fehling's solution

2. Schiff's reagent

3. Ammonia

4. Ammoniacal ${\mathrm{AgNO}}_3$

Product P in the above reaction is -

1. 

2. 

3. 

4. 

Cyanohydrin of which compound gives lactic acid on hydrolysis?

1. Acetone                                 

2. Acetaldehyde

3. Propanal                                 

4. HCHO

In this reaction,

CH₃CHO + HCN $\to$CH₃CH(OH)CN $\stackrel{\mathrm{H}.\mathrm{OH}}{\to }$CH₃CH(OH)COOH

an asymmetric compound is generated. The acid obtained would be            

1. 50% D + 50% L-isomer

2. 20% D + 80% L-isomer

3. D-isomer

4. L-isomer

The enolic form of acetone contains:

1. 9 $\mathrm{\sigma }$-bonds, 1$\mathrm{\pi }$-bond and 2 lone pairs

2. 8 $\mathrm{\sigma }$-bonds, 2$\mathrm{\pi }$-bonds and 2 lone pairs

3. 10 $\mathrm{\sigma }$-bonds, 1$\mathrm{\pi }$-bond and 1 lone pair

4. 9 $\mathrm{\sigma }$-bonds, 2$\mathrm{\pi }$-bonds and 1 lone pair

Nucleophilic addition reaction will be most favoured in                   [2006]

1. $$
$\mathrm{O}$
$\parallel$
${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{C}-{\mathrm{CH}}_3$

2. $({\mathrm{CH}}_3{)}_2\mathrm{C}=\mathrm{O}$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CHO}$

4. ${\mathrm{CH}}_3\mathrm{CHO}$

Acetaldehyde normally reacts with                

1. only electrophiles

2. only nucleophiles

3. only free radicals

4. both electrophiles and nucleophiles

Benzaldehyde and acetaldehyde can be distinguished by:

1. Iodoform test

2. 2,4 - DNP test

3. ${\mathrm{NH}}_3$ reaction

4. Wolff-Kishner's reduction

A and B in the following reactions are  

1. A=RR'CH₂CN,              B=NaOH

2. A=RR'C${<}_{\mathrm{COOH}}^{\mathrm{OH}}$ ,          B=CH₃

3. A=RR'C${<}_{\mathrm{COOH}}^{\mathrm{CN}}$ ,          B=CH₃

4. A=RR"C${<}_{\mathrm{OH}}^{\mathrm{CN}}$,              B=LiAlH₄

Acetone reacts with iodine (I₂) to form iodoform in the presence of      

1. CaCO₃   

2. NaOH     

3. KOH     

4. MgCO₃