Choose the pairs of isoelectronic compounds which are isostructural:
1. TeF2, XeF2
2. IBr2-, XeF2
3. IF3, XeF2
4. BeCl2, XeF2
Which of the following reactions does not exhibit the oxidising behaviour of H2SO4?
1. Cu + 2H2SO4 → CuSO4 + SO2 + 2H2O
2. 3S + 2H2SO4 → 3SO2 + 2H2O
3. C + 2H2SO4 → CO2 + 2SO2 + 2H2O
4. CaF2 + H2SO4 → CaSO4 + 2HF
In the structure of ClF3, the number of lone pairs of electrons on central atom 'Cl' is:
1. 1
2. 2
3. 3
4. 4
Match the compounds given in Column I with the shape given in Column II and mark the correct option.
Column I | Column II | ||
A. | XeF6 | 1. | Distorted octahedral |
B. | XeO3 | 2. | Square planar |
C. | XeOF4 | 3. | Pyramidal |
D. | XeF4 | 4. | Square pyramidal |
1. | A-1, B-2, C-4, D-3 | 2. | A-4, B-3, C-1, D-2 |
3. | A-4, B-1, C-2, D-3 | 4. | A-1, B-3, C-4, D-2 |
1. | Phosphinic acid is a monoprotic acid while phosphonic acid is a diprotic acid |
2. | Phosphinic acid is a diprotic acid while phosphonic acid is a monoprotic acid |
3. | Both are triprotic acids |
4. | Both are diprotic acids |
Which of the statements given below is incorrect?
1. \(\mathrm{C l_{2} O_{7 }}\)is an anhydride of perchloric acid
2. \(\mathrm{O_{3}}\) molecule is bent
3. ONF is isoelectronic with \(\mathrm{N O_{2}^{-}}\)
4. \(\mathrm{O F_{2}}\) is an oxide of fluorine
The variation of the boiling point of the hydrogen halides is in the order HF > HI > HBr > HCl.
The higher boiling point of hydrogen fluoride is explained as:
1. | The electronegativity of flourine is much higher than other elements in group |
2. | There is strong hydrogen bonding between HF molecules |
3. | The bond energy of HF molecules is greater than in other hydrogen halides |
4. | The effect of nuclear shielding is much reduced in flourine which polarizes the HF molecule |
The strong reducing behaviour of H3PO2 is due to:
1. Presence of one -OH group and two P-H bonds.
2. High electron gain enthalpy of phosphorus.
3. High oxidation state of phosphorus.
4. Presence of two -OH groups and one P-H bond.
The acidity of diprotic acids in aqueous solution increases in the order:
1. H2S < H2Se < H2Te
2. H2Se < H2S < H2Te
3. H2Te < H2S < H2Se
4. H2Se < H2Te < H2S