A common emitter amplifier has a voltage gain of 50, an input impedance of 100 Ω and an output impedance of 200 Ω. The power gain of the amplifier is:
1. 500
2. 1000
3. 1250
4. 50
To get an output Y = 1 from the circuit shown below, the input must be:
1. A=0 B=1 C=0
2. A=0 B=0 C=1
3. A=1 B=0 C=1
4. A=1 B=0 C=0
The symbolic representation of four logic gates is as shown:
(i) | (ii) | ||
(ii) | (iv) |
The logic symbols for OR, NOT, and NAND gates are respectively:
1. (iii), (iv), (ii)
2. (iv), (i), (iii)
3. (iv), (ii), (i)
4. (i), (iii), (iv)
The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain without feedback will be:
1. 90
2. 10
3. 1.25
4. 100
A p-n photodiode is made of a material with a bandgap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly:
1.
2.
3.
4.
The circuit is equivalent to:
1. AND gate
2. NAND gate
3. NOR gate
4. OR gate
In the following circuit, the output \(Y\) for all possible inputs \(A\) and \(B\) is expressed by the truth table:
1. | A | B | Y | 2. | A | B | Y |
0 | 0 | 0 | 0 | 0 | 1 | ||
0 | 1 | 0 | 0 | 1 | 1 | ||
1 | 0 | 0 | 1 | 0 | 1 | ||
1 | 1 | 1 | 1 | 1 | 0 | ||
3. | 0 | 0 | 1 | 4. | 0 | 0 | 0 |
0 | 1 | 0 | 0 | 1 | 1 | ||
1 | 0 | 0 | 1 | 0 | 1 | ||
1 | 1 | 1 | 1 | 1 | 1 |
In the energy band diagram of a material shown below, the open circles and filled circles denote holes and electrons respectively. The material is a/an:
1. p-type semiconductor
2. insulator
3. metal
4. n-type semiconductor
A transistor is operated in a common emitter configuration at constant collector voltage Vc = 1.5 V such that a change in the base current from 100 μA to 150 μA produces a change in the collector current from 5 mA to 10 mA. The current gain (β) is:
1. 67
2. 75
3. 100
4. 50