Two simple harmonic motions of angular frequencies 100 and 1000 rad s^-1 have the same displacement amplitude. The ratio of their maximum acceleration is:

1. 1: 10
2. 1: 10²
3. 1: 10³
4. 1: 10⁴

Two points are located at a distance of \(10\) m and \(15\) m from the source of oscillation. The period of oscillation is \(0.05\) s and the velocity of the wave is \(300\) m/s. What is the phase difference between the oscillations of two points?
1. \(\frac{\pi}{3}\)
2. \(\frac{2\pi}{3}\)
3. \(\pi\)
4. \(\frac{\pi}{6}\)

A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is:
1. $\frac{\mathrm{T}}{4}$
2. $\frac{\mathrm{T}}{8}$
3. $\frac{\mathrm{T}}{12}$
4. $\frac{\mathrm{T}}{2}$

A mass of \(2.0\) kg is put on a flat pan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released, the mass executes a simple harmonic motion. The spring constant is \(200\) N/m. What should be the minimum amplitude of the motion, so that the mass gets detached from the pan? 
(Take \(g=10\) m/s²) 
                

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is:
1. 0.5$\mathrm{\pi }$
2. $\mathrm{\pi }$
3. 0.707$\mathrm{\pi }$
4. zero

A rectangular block of mass m and area of cross-section A floats in a liquid of density ρ. If it is given a small vertical displacement from equilibrium, it undergoes oscillation with a time period T. Then:
1. $T\propto \sqrt{\rho }$
2. $T\propto \frac{1}{\sqrt{A}}$
3. $T\propto \frac{1}{\rho }$
4. $T\propto \frac{1}{\sqrt{m}}$

The average velocity of a particle executing SHM in one complete vibration is:
1. zero
2. \(\dfrac{A \omega}{2}\)
3. \(A \omega\)
4. \(\dfrac{A \left(\omega\right)^{2}}{2}\)