In the following circuit, the output \(Y\) for all possible inputs \(A\) and \(B\) is expressed by the truth table: 
    

1. A B Y 2. A B Y
0 0 0 0 0 1
0 1 0 0 1 1
1 0 0 1 0 1
1 1 1 1 1 0
3. 0 0 1 4. 0 0 0
0 1 0 0 1 1
1 0 0 1 0 1
1 1 1 1 1 1

Subtopic:  Logic gates |
 75%
From NCERT
AIPMT - 2007
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In the energy band diagram of a material shown below, the open circles and filled circles denote holes and electrons respectively. The material is a/an: 

1. p-type semiconductor

2. insulator

3. metal

4. n-type semiconductor

Subtopic:  Energy Band theory |
 72%
From NCERT
AIPMT - 2007
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A transistor is operated in a common emitter configuration at constant collector voltage Vc = 1.5 V such that a change in the base current from 100 μA to 150 μA produces a change in the collector current from 5 mA to 10 mA. The current gain (β) is:

1. 67

2. 75

3. 100

4. 50

Subtopic:  Applications of Transistor (OLD NCERT) |
 68%
From NCERT
AIPMT - 2006
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Which of the following is an example of forward biasing?
 

1. 2.
3. 4.
Subtopic:  PN junction |
 83%
From NCERT
AIPMT - 2006
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The following figure shows a logic gate circuit with two inputs A and B and the output C. The voltage waveforms of A, B, and C are as shown below:
   
The logic circuit gate is:

1. AND gate

2. NAND gate

3. NOR gate

4. OR gate

Subtopic:  Logic gates |
 74%
From NCERT
AIPMT - 2006
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The correct Boolean operation represented by the circuit diagram given above is:
 
1. \(\mathrm{NOR}\)
2. \(\mathrm{AND}\)
3. \(\mathrm{OR}\)
4. \(\mathrm{NAND}\)

Subtopic:  Logic gates |
 51%
From NCERT
NEET - 2019
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The circuit is equivalent to: 
     

1. AND gate
2. NAND gate
3. NOR gate
4. OR gate

Subtopic:  Logic gates |
 75%
From NCERT
AIPMT - 2008
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\(\mathrm{p\text-n}\) photodiode is fabricated from a semiconductor with a band gap of \(2.5\) eV. It can detect a signal of wavelength:
1. \(6000~\mathring{A}\)
2. \(4000\) nm
3. \(6000\) nm
4. \(4000~\mathring{A}\)  
Subtopic:  Energy Band theory |
 63%
From NCERT
AIPMT - 2009
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To get an output Y = 1 from the circuit shown below, the input must be:

 

1. A=0 B=1 C=0

2. A=0 B=0 C=1

3. A=1 B=0 C=1

4. A=1 B=0 C=0

Subtopic:  Logic gates |
 91%
From NCERT
AIPMT - 2010
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A common emitter amplifier has a voltage gain of 50, an input impedance of 100 Ω and an output impedance of 200 Ω. The power gain of the amplifier is:

1. 500

2. 1000

3. 1250

4. 50

Subtopic:  Applications of Transistor (OLD NCERT) |
 72%
From NCERT
AIPMT - 2010
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