Two radioactive substances A and B have decay constants 5λ and λ respectively. At t = 0, they have the same number of nuclei. The ratio of the number of nuclei of A to those of B will be 1e21e2 after a time interval:

1. 14λ14λ

2. 4λ4λ

3. 2λ2λ

4. 12λ12λ

Subtopic:  Radioactivity (OLD NCERT) |
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From NCERT
AIPMT - 2007
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The binding energy of deuteron is 2.2 MeV2.2 MeV and that of 2He42He4 is 28 MeV28 MeV. If two deuterons are fused to form one 2He42He4then the energy released is:
1. 25.8 MeV25.8 MeV
2. 23.6 MeV23.6 MeV
3. 19.2 MeV19.2 MeV
4. 30.2 MeV30.2 MeV

Subtopic:  Nuclear Binding Energy |
 74%
From NCERT
AIPMT - 2006
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In a radioactive material, the activity at time t1 is R1 and at a later time t2, it is R2. If the decay constant of the material is λ, then:

1. R1=R2eλ(t1+t2)R1=R2eλ(t1+t2)

2. R1=R2e-λ(t1-t2)R1=R2eλ(t1t2)

3. R1=R2(t1-t2)R1=R2(t1t2)

4. R1=R2R1=R2

Subtopic:  Radioactivity (OLD NCERT) |
 71%
From NCERT
AIPMT - 2006
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A nucleus ZXAZXA has a mass represented by M(A,Z).M(A,Z). If MPMP and MnMn denote the mass of proton and neutron respectively and BE the binding energy, then:

1. BE=[M(A,Z)-ZMp-(A-Z)Mn]c2BE=[M(A,Z)ZMp(AZ)Mn]c2

2. BE=[ZMp+(A-Z)Mn-M(A,BE=[ZMp+(AZ)MnM(A, Z)]c2Z)]c2

3. BE=[ZMp+AMn-M-(A,BE=[ZMp+AMnM(A, Z)]c2Z)]c2

4. BE=M(A,BE=M(A, Z)-ZMp-(A-Z)MnZ)ZMp(AZ)Mn

Subtopic:  Nuclear Binding Energy |
 83%
From NCERT
AIPMT - 2007
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In the radioactive decay process, the negatively charged emitted β-particles are:

1. the electrons present inside the nucleus
2. the electrons produced as a result of the decay
of neutrons inside the nucleus
3. the electrons produced as a result of collisions
between atoms
4. the electrons orbiting around the nucleus

Subtopic:  Types of Decay |
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AIPMT - 2007
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Two nuclei have their mass numbers in the ratio of 1:3.1:3. The ratio of their nuclear densities would be:
1. 1:31:3
2. 3:13:1
3. (3)1/3:1(3)1/3:1
4. 1:11:1

Subtopic:  Nucleus |
 80%
From NCERT
AIPMT - 2008
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If M(A, Z)M(A, Z)MpMp, and MnMn denote the masses of the nucleus AZX,AZX, proton, and neutron respectively in units of uu (1 u=931.5 MeV/c2)(1 u=931.5 MeV/c2) and represent its binding energy (BE)(BE) in MeVMeV. Then:

1. M(A,Z)=ZMp+(AZ)MnBEc2M(A,Z)=ZMp+(AZ)MnBEc2
2. M(A,Z)=ZMp+(AZ)Mn+BEM(A,Z)=ZMp+(AZ)Mn+BE
3. M(A,Z)=ZMp+(AZ)MnBEM(A,Z)=ZMp+(AZ)MnBE
4. M(A,Z)=ZMp+(AZ)Mn+BEc2M(A,Z)=ZMp+(AZ)Mn+BEc2
Subtopic:  Mass-Energy Equivalent |
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AIPMT - 2008
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The decay constants of two radioactive materials X1 and X2 are 5λ5λ and λλ respectively. Initially, they have the same number of nuclei.  The ratio of the number of nuclei of X1 to that of X2  will be 1/e1/e after a time:
1. λλ

2. 12λ12λ

3. 14λ14λ

4. eλeλ

Subtopic:  Types of Decay |
 78%
From NCERT
AIPMT - 2008
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The number of beta particles emitted by a radioactive substance is twice the number of alpha particles emitted by it. The resulting daughter is an:

1. isobar of a parent. 2. isomer of a parent.
3. isotone of a parent. 4. isotope of a parent.
Subtopic:  Types of Decay |
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From NCERT
AIPMT - 2009
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In the nuclear decay given below:
AZXAZ+1YA4Z1BA4Z1BAZXAZ+1YA4Z1BA4Z1B the particles emitted in the sequence are:
1. β,α,γβ,α,γ 2. γ,β,αγ,β,α
3. β,γ,αβ,γ,α 4. α,β,γα,β,γ
Subtopic:  Types of Decay |
 90%
From NCERT
AIPMT - 2009
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