Assertion (A): 1 g O2 and 1 g O3  have an equal number of oxygen atoms.
Reason (R): O2  and  O3  have different molar masses.
 
1. Both A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Moles, Atoms & Electrons |
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Match the following physical quantities with units.

Physical quantity Unit
A. Molarity 1.  mol kg–1 
B.  Molality 2. mol L–1
C.  Pressure 3.  Candela
D. Luminous intensity 4. Pascal

Codes:

A B C D
1. 1 4 2 3
2. 2 1 4 3
3. 1 4 3 2
4. 4 1 3 2
Subtopic:  Introduction |
 94%
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The correct match is:
List I List II
a. Micro i.  10-15 m
b. Mega ii.  10-6 m
c. Giga iii.  106 m
d. Femto iv.  109 m
Codes:
a b c d
1. i iv iii ii
2. iii iv ii i
3. ii iii iv i
4. i iii iv ii
Subtopic:  Introduction |
 87%
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At 100 ºC and 1 atm, if the density of liquid water is 1.0 g cm–3 and that of water vapor is 0.0006 g cm-3, then the volume occupied by water molecules in 1 litre of steam at that temperature will be:

1. 6 cm 2. 60 cm3
3. 0.6 cm3  4. 0.06 cm3
Subtopic:  Moles, Atoms & Electrons |
 59%
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At STP, the density of CCl4 vapour in g/L will be closest to: 

1. 8.67

2. 6.87

3. 3.67

4. 4.26

Subtopic:  Concentration Based Problem |
 76%
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A reading on Fahrenheit scale is 200°F. The same reading on celsius scale will be :
1. 40°C
2. 94°C
3. 93°C
4. 30°C

Subtopic:  Introduction |
 68%
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The numbers 234,000 and 6.0012 can be represented in scientific notation as:

1. 2.34×10-9 and 6×103

2. 0.234 ×10-6 and 60012×10-9

3. 2.34×10-9 and 6.0012×10-9

4. 2.34×105 and 6.0012×100

Subtopic:  Introduction |
 85%
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ln the final answer of the expression \(\large{\frac{(29.2-20.2)\times(1.79\times10^5)}{1.37}}\)
the number of significant figures after solving the expression is:

1. 2 2. 4
3. 6 4. 7
Subtopic:  Introduction |
 59%
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The number of significant figures in the numbers 5005, 500.0, and 126,000 are, respectively: 

1. 2, 4, and 3  2. 4, 1, and 3 
3. 4, 4, and 6  4. 4, 4, and 3 
Subtopic:  Introduction |
 58%
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If 0.5 moles of BaCl2 is reacted with 0.2 moles of Na3PO4 then the maximum moles of Ba3(PO4)2 formed is:

1. 0.33 2. 0.25
3. 0.10 4. 0.52
Subtopic:  Limiting Reagent |
 72%
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