A hypothetical electrochemical cell is shown below.
A|A+(x M) || B+(y M)|B
The Emf measured is +0.20 V. The cell reaction is:

1. A+ + B → A + B+

2.  A+ + e- → A ; B+ + e- → B

3. The cell reaction cannot be predicted.

4. A + B+ → A+ + B

Subtopic:  Electrochemical Series | Nernst Equation |
 75%
From NCERT
AIPMT - 2006
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The voltage of the cell given below increases with: 

Cell: Sn(s) + 2Ag+(aq) → Sn2+(aq) + 2Ag(s)

1. Increase in size of the silver rod.

2. Increase in the concentration of Sn2+ ions.

3. Increase in the concentration of Ag+ ions.

4. None of the above.

Subtopic:  Nernst Equation |
 61%
From NCERT
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The change in reduction potential of a hydrogen electrode when its solution initialy at pH = 0 is neutralised to pH = 7, is a/an-

1. Increase by 0.059 V 2. Decrease by 0.059 V
3. Increase by 0.41 V 4. Decrease by 0.41 V
Subtopic:  Electrode & Electrode Potential | Nernst Equation |
 52%
From NCERT
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By how much will the potential of half cell Cu2+| Cu change if the solution is diluted to 100 times at 298 K. It will -

1. Increase by 59 mV 2. Decrease by 59 mV
3. Increase by 29.5 mV 4. Decrease by 29.5 mV
Subtopic:  Nernst Equation |
 56%
From NCERT
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At 298 K the Emf of the following cell is:

\(\small{Pt|H_{2}(1 \ atm)|H^{+}(0.02 \ M) \ || \ H^{+}(0.01 \ M)|H_{2}(1 \ atm)|Pt}\)

1. - 0.017 V

2. 0.0295 V

3. 0.1 V

4. 0.059 V

Subtopic:  Nernst Equation |
 59%
From NCERT
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In the electrochemical cell:

Zn|ZnSO4(0.01 M) || CuSO4(1.0M),Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 is changed to 0.01 M, the emf changes to E2. The relationship between E1 and E2 is : 
( Given, RT= 0.059)

1. E1 = E2

2. E1 < E2

3. E1 > E2

4. E2 = 0 ≠ E1

Subtopic:  Electrode & Electrode Potential | Nernst Equation |
 69%
From NCERT
NEET - 2017
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The pressure of H2 required to make the potential of H- electrode zero in pure water at 298 K is:

1. 10–12  atm 2. 10–10  atm
3. 10–4  atm 4. 10–14 atm
Subtopic:  Nernst Equation |
 67%
From NCERT
NEET - 2016
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For the cell, Ti/Ti+(0.001M)||Cu2+(0.1M)|Cu, Ecello at

25 °C is 0.83 V. Ecell can be increased :

1. By increasing [Cu2+]

2. By increasing [Ti+]

3. By decreasing [Cu2+]

4. None of the above.

Subtopic:  Nernst Equation | Faraday’s Law of Electrolysis |
 71%
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Given the following cell:

\(\small{Pt(s)|Br_{2}(l)|Br^{-}(0.010 \ M)\ || H_{2}(g)(1\ bar)|H^{+}(0.030 \ M)|Pt(s)}\)

If the concentration of \(Br^-\) becomes 2 times and the concentration of \(H^+\) becomes half of the initial value, then emf of the cell will become:

1. Two times.

2. Four times.

3. Eight times.

4. Remains the same.

Subtopic:  Nernst Equation |
 53%
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The electrode potential of Cu electrode dipped in 0.025 M CuSO4 solution at 298 K is:

(standard reduction potential of Cu = 0.34 V)

1. 0.047 V

2. 0.293 V

3. 0.35 V

4. 0.387 V

Subtopic:  Nernst Equation |
 62%
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