The correct order of \(\mathrm{C-O}\) bond length among \(\mathrm{CO},\mathrm{CO}_3^{2-},\) and \(\mathrm{CO_2}\) is :
1. \(\mathrm{CO}_2<\mathrm{CO}_3^{2-}<\mathrm{CO} \)
2. \(\mathrm{CO}<\mathrm{CO}_3^{2-}<\mathrm{CO}_2 \)
3. \(\mathrm{CO}_3^{2-}<\mathrm{CO}_2<\mathrm{CO} \)
4. \(\mathrm{CO}<\mathrm{CO}_2<\mathrm{CO}_3^{2-}\)
Mg2C3 reacts with water forming propyne . The number of sigma and pie bonds in \(C_{3}^{4-}\)is-
1. Two sigma and two pi bonds.
2. Three sigma and one pi bonds.
3. Two sigma and one pi bonds.
4. Two sigma and three pi bonds.
Which of the following pairs of ions are isoelectronic and isostructural?
1.
2.
3.
4.
Match the compounds given in Column I with the hybridization and shape given in Column II and mark the correct option.
Column I | Column II |
A. XeF6 | 1. Distorted octahedral |
B. XeO3 | 2. Square planar |
C. XeOF4 | 3. Pyramidal |
D. XeF4 | 4. Square pyramidal |
A | B | C | D | |
1. | 1 | 2 | 4 | 3 |
2. | 4 | 3 | 1 | 2 |
3. | 4 | 1 | 2 | 3 |
4. | 1 | 3 | 4 | 2 |
has a net dipole moment while
\(BeF_2\) has zero dipole moment because :
1. F is more electronegative than oxygen.
2. Be is more electronegative than oxygen.
3. molecule is linear and \(BeF_2\) is bent.
4. molecule is linear and is bent.
The correct order of electronegativity of hybrid orbitals of carbon is:
1. sp > sp2 < sp3
2. sp > sp2 > sp3
3. sp < sp2 > sp3
4. sp < sp2 < sp3
Amongst the one with the highest boiling point is:
1. H2O because of H-bonding.
2. H2Te because of higher molecular weight.
3. H2S because of H-bonding.
4. H2Se because of lower molecular weight.
Combination of atoms A and B that forms an anti-bonding molecular orbital is :
1.
2.
3.
4.
The correct order of increasing dipole moment is :
1. < < <
2. < < <
3. < < <
4. < < <
A pair in which both species are not likely to exist is:
1. | \(H^+_2,He^{2-}_2\) | 2. | \(H^-_2,He^{2+}_2\) |
3. | \(H^{2+}_2,He_2\) | 4. | \(H^+_2,He^{2+}_2\) |