An organic compound A on reduction gives compound B which on reaction with chloroform and potassium hydroxide forms C. The compound C on catalytic reduction gives N-methylaniline. The compound A is                                                               

1. Nitrobenzene

2. Nitromethane

3. Methylamine

4. Aniline

Subtopic:  Urea & Nitro Compound |
 68%
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Acetamide and ethyl amine can be distinguished by reacting with:            

1. Aq. HCl and heat

2. Aq. NaOH and heat

3. Acidified KMnO4

4. Bromine water

Subtopic:  Amines - Preparation & Properties | Identification of Primary, Secondary & Tertiary Amines | Mechanism |
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Which of the following compound gives dye test

1. Aniline               

2. Methylamine                 

3. Diphenylamine                 

4. Ethylamine

Subtopic:  Diazonium Salts: Preparation, Properties & Uses |
 63%
From NCERT
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CH3CH2ClNaCNXNi/H2YAcetic anhydrideZ

In the above reaction sequence, Z is                                  

1. CH3CH2CH2NHCOCH3

2. CH3CH2CH2NH2

3. CH3CH2CH2CONHCH3

4. CH3CH2CH2CONHCOCH3

Subtopic:  Cyanides & Isocyanides |
 73%
From NCERT
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Predict the product,                               

1. 

2. 

3. 

4. 

 

Subtopic:  Amines - Preparation & Properties |
 51%
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Aniline in a set of reactions yield the following products                                                   

The structure of the product D would be -

1. C6H5CH2NH2

2. C6H5NHCH2CH3

3. C6H5NHOH

4. C6H5CH2OH

Subtopic:  Cyanides & Isocyanides | Diazonium Salts: Preparation, Properties & Uses |
 61%
From NCERT
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Intermediates formed during the reaction of RCONH2 with Br2 and KOH are -                               

1. RCONHBr and RNCO

2. RNHCOBr and RNCO

3. RNHBr and RCONHBr

4. RCONBr2

Subtopic:  Amines - Preparation & Properties |
 60%
From NCERT
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In a reaction of aniline a colored product C was obtained.

The structure of C would be

1. 

2. 

3. 

4. 

Subtopic:  Diazonium Salts: Preparation, Properties & Uses |
 74%
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Product Q in the above reaction is             

1.  

2.  

3.  

4.  

Subtopic:  Cyanides & Isocyanides |
 60%
From NCERT
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The final product C in the below mentioned reaction is:
\(\xrightarrow[]{Ac_2O}\ A\ \xrightarrow[CH_3COOH]{Br_2}\ B\ \xrightarrow[H^+]{H_2O}\ C\)

1.  2.
3. 4.
Subtopic:  Mechanism |
 64%
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