The hybridization of orbitals of N atom in are respectively:
1.
2.
3.
4.
Given the following hydrocarbon:
The state of hybridisation of carbons marked 2, 3, 5 and 6 in the following hydrocarbon are, respectively :
1. sp, sp3, sp2 and sp3
2. sp3, sp2, sp2 and sp
3. sp, sp2, sp2 and sp3
4. sp, sp2 sp3 and sp2
The correct order of electronegativity of hybrid orbitals of carbon is:
1. sp > sp2 < sp3
2. sp > sp2 > sp3
3. sp < sp2 > sp3
4. sp < sp2 < sp3
Which of the following species has a bond angle of \(120^\circ\)?
1. \(\mathrm{{SF}_6}\)
2. \(\mathrm{NCl_3}\)
3. \(\mathrm{BCl_3}\)
4. \(\mathrm{PH_3}\)
Match the compounds of Xe in column I with the molecular structure in column II.
Column-I | Column-II |
(a) | (i) Square planar |
(b) | (ii) Linear |
(c) | (iii) Square pyramidal |
(d) | (iv) Pyramidal |
(a) | (b) | (c) | (d) | |
1. | (ii) | (i) | (iii) | (iv) |
2. | (ii) | (iv) | (iii) | (i) |
3. | (ii) | (iii) | (i) | (iv) |
4. | (ii) | (i) | (iv) | (iii) |
Match the compounds given in Column I with the hybridization and shape given in Column II and mark the correct option.
Column I | Column II |
A. XeF6 | 1. Distorted octahedral |
B. XeO3 | 2. Square planar |
C. XeOF4 | 3. Pyramidal |
D. XeF4 | 4. Square pyramidal |
A | B | C | D | |
1. | 1 | 2 | 4 | 3 |
2. | 4 | 3 | 1 | 2 |
3. | 4 | 1 | 2 | 3 |
4. | 1 | 3 | 4 | 2 |
Mg2C3 reacts with water forming propyne . The number of sigma and pie bonds in \(C_{3}^{4-}\)is-
1. Two sigma and two pi bonds.
2. Three sigma and one pi bonds.
3. Two sigma and one pi bonds.
4. Two sigma and three pi bonds.