The quantum numbers of four electrons are given below:
I. n=4; l=2; \(m_l\)=-2; s=-\(\frac1{2}\)
II. n=3; l=2; \(m_l\)=1; s=+\(\frac1{2}\)
III. n=4; l=1; \(m_l\)=0; s=+\(\frac1{2}\)
IV. n=3; l=1; \(m_l\)=-1; s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is: