Which of the following complexes formed by Cu++ ions is most stable?

1. Cu2+ + 4NH3 → [Cu(NH3)4]2+   logK = 11.6
2. Cu2+ + 4CN- → [Cu(CN)4]2-    logK = 27.3
3. Cu2+ + 2en- → [Cu(en)2]2+     logK =  15 .4
4. Cu2+   +   4H2O → [Cu(H2O)4]2+     logK = 8.9
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The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of the wavelength of light in the visible region for the complexes?

\(1. \ \left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \\ 2. \ \left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} \\ 3. \ \left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-} \\ 4. \ \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\)

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The CFSE for octahedral  CoCl64- is 18,000 cm-1 . The CFSE for tetrahedral will be \(\mathrm{CoCl}_4{ }^{2-}\):\(\mathrm{CoCl}_4{ }^{2-}\)

1. 6000 cm-1

2. 16,000 cm-1

3. 18,000 cm-1

4. 8,000 cm-1

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Atomic number of Mn Fe and Co are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

a. CoNH363+

b. Mn(CN)63-

c.  Fe(CN)64-

d.  FeCN63-

Choose the correct option
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

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Identify the outer orbital octahedral complexes among the following that have the same number of unpaired electrons:
(Atomic numbers of Mn, Fe, Co, and Ni are 25, 26, 27, and 28 respectively)

(a) MnCl63- (b) FeF63-
(c) CoF63- (d) NiNH362+


1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

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An aqueous pink solution of cobalt(II) chloride changes to deep blue on addition of excess of HCl. This is because ........

1. CoH2O62+ is transformed into CoCl64-
2. CoH2O62+ is transformed int\(CoCl^{2-}_4\)
3. Tetrahedral complexes have smaller crystal field splitting than octahedral complexes.
4. Tetrahedral complexes have larger crystal field splitting than octahedral complex 

Choose the correct option
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

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Match the complex ions give in Column I with the colours given in column II and assign the correct code.

               Column I

            (Complex ion)

              Column II

              (Colour)

A. [Co(NH3)6]3+

1. Violet

B. [Ti(H2O)6)]3+

2. Green

C. Ni(H2O62+

3. Pale blue 

D. Ni(H2O)4(en)2+

4. Yellowish orange

Codes:

Options:  A   B   C   D 
1. 2 3 4 1
2. 3 1 5 2
3. 5 4 3 2
4. 4 3 2 1
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 Match the complex ions given in Column I with the hybridization and number of unpaired electrons given in Column II and assign the correct code. 

Column l 

Column II

(Hybridisation, number of unpaired electrons)

A. Cr(H2O)63+

1. dsp2, 1

B.Co(CN)42-

2. sp3d2, 5

C.Ni(NH3)62+

3. d2sp3, 3

D.MnF64-

4. sp3d2, 2

Codes: 

Options:  B   C   D 
1. 2 3 4 1
2. 3 1 4 2
3. 5 4 3 2
4. 4 5 3
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Assertion (A): Cr(H2O6)Cl2 and Fe(H2O)6Cl2 are reducing in nature.
Reason (R): Unpaired electrons are present in their d-orbitals.

 

1. Both (A) and (R) are True and the (R) is the correct explanation of (A).
2. Both (A) and (R) are True and (R) is not the correct explanation of (A).
3. (A) is true but the (R) is False.
4. (A) is False but (R) is True.
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Assertion (A): Fe(CN)63- ion shows magnetic moment corresponding to two unpaired electrons.
Reason(R): Because it has d2sp3 type hybridization.

 

1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True and (R) is not the correct explanation of (A).
3. (A) is True but the (R) is False.
4. (A) is False but the (R) is True.
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