A satellite of mass \(m\) is orbiting the earth (of radius \(R\)) at a height \(h\) from its surface. What is the total energy of the satellite in terms of \(g_0?\)
(\(g_0\) is the value of acceleration due to gravity at the earth's surface)

1. \(\dfrac{mg_0R^2}{2(R+h)}\) 2. \(-\dfrac{mg_0R^2}{2(R+h)}\)
3. \(\dfrac{2mg_0R^2}{(R+h)}\) 4. \(-\dfrac{2mg_0R^2}{(R+h)}\)
Subtopic:  Gravitational Potential Energy |
 78%
From NCERT
NEET - 2016
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The work done to raise a mass \(m\) from the surface of the earth to a height \(h\), which is equal to the radius of the earth, is:
1. \(\dfrac{3}{2}mgR\)
2. \(mgR\)
3. \(2mgR\)
4. \(\dfrac{1}{2}mgR\)  
Subtopic:  Gravitational Potential Energy |
 66%
From NCERT
NEET - 2019
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A body of mass \(m\) is taken from the Earth’s surface to the height equal to twice the radius \((R)\) of the Earth. The change in potential energy of the body will be: 

1. \(\frac{2}{3}mgR\) 2. \(3mgR\)
3. \(\frac{1}{3}mgR\) 4. \(2mgR\)
Subtopic:  Gravitational Potential Energy |
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From NCERT
AIPMT - 2013
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An artificial satellite moving in a circular orbit around the earth has a total (kinetic + potential) energy \(E_0.\) Its potential energy is:
1. \(-E_0\)
2. \(1.5E_0\)
3. \(2E_0\)
4. \(E_0\)
Subtopic:  Gravitational Potential Energy |
 82%
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A particle is released from a height of \(S\) above the surface of the earth. At a certain height, its kinetic energy is three times its potential energy. The distance from the earth's surface and the speed of the particle at that instant are respectively:
1. \(\frac{S}{2},\frac{\sqrt{3gS}}{2}\) 2. \(\frac{S}{4}, \sqrt{\frac{3gS}{2}}\)
3. \(\frac{S}{4},\frac{3gS}{2}\) 4. \(\frac{S}{4},\frac{\sqrt{3gS}}{3}\)
Subtopic:  Gravitational Potential Energy |
 70%
From NCERT
NEET - 2021
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If a particle is dropped from a height \(h = 3R\) from the Earth's surface, the speed with which the particle will strike the ground is:
1. \(\sqrt{3gR}\)
2. \(\sqrt{2gR}\)
3. \(\sqrt{1.5gR}\)
4. \(\sqrt{gR}\)

Subtopic:  Gravitational Potential Energy |
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Given below are two statements: 

Assertion (A): When a body is raised from the surface of the earth, its potential energy increases.
Reason (R): The potential energy of a body on the surface of the earth is zero.
  
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Gravitational Potential Energy |
 55%
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An object of mass \(m\) is placed at a height \(R_{e}\) from the surface of the earth. What is the increase in potential energy of the object if the height of the object is increased to \(2R_{e}\) from the surface? (\(R_{e}:\) Radius of the earth)
1. \({\dfrac{1}{3}{mgR}_{e}}\)
2. \({\dfrac{1}{6}{mgR}_{e}}\)
3. \({\dfrac{1}{2}{mgR}_{e}}\)
4. \({\dfrac{1}{4}{mgR}_{e}}\)
Subtopic:  Gravitational Potential Energy |
 57%
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The gravitational potential energy of a particle of mass \(m\) increases by \(mgh,\) when it is raised through a height \(h\) in a uniform gravitational field "\(g\)". If a particle of mass \(m\) is raised through a height \(h\) in the earth's gravitational field (\(g\): the field on the earth's surface) and the increase in gravitational potential energy is \(U\), then:
1. \(U > mgh\)
2. \(U < mgh\)
3. \(U = mgh\)
4. any of the above may be true depending on the value of \(h,\) considered relative to the radius of the earth.
Subtopic:  Gravitational Potential Energy |
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