A parallel plate air capacitor has capacitance \(C,\) the distance of separation between plates is \(d\) and potential difference \(V\) is applied between the plates. The force of attraction between the plates of the parallel plate air capacitor is:
1. | \(\frac{C^2V^2}{2d}\) | 2. | \(\frac{CV^2}{2d}\) |
3. | \(\frac{CV^2}{d}\) | 4. | \(\frac{C^2V^2}{2d^2}\) |
A parallel plate air capacitor is charged to potential difference \(V\). After disconnecting the battery, the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates:
1. | decreases. | 2. | increases. |
3. | becomes zero. | 4. | does not change. |
The electrostatic force between the metal plates of an isolated parallel plate capacitor \(C\) having a charge \(Q\) and area \(A\) is:
1. | independent of the distance between the plates. |
2. | linearly proportional to the distance between the plates. |
3. | proportional to the square root of the distance between the plates. |
4. | inversely proportional to the distance between the plates. |
In the given figure if \(V = 4~\text{volt}\) each plate of the capacitor has a surface area of\(10^{-2}~\text{m}^2\) and the plates are \(0.1\times10^{-3}~\text{m}\)apart, then the number of excess electrons on the negative plate is:
1. | depends on the square of surface charge density. |
2. | depends on the separation between the plates. |
3. | depends directly on the plate area of each plate. |
4. | depends directly on the dielectric constant of the medium. |
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