The structure of C in the above mentioned reaction is -

1. 

2. 

3. 

4. 

Semicarbazide, among the following, is:

1. NH₂CONH₂

2. NH₂-NH₂

3. NH₂CONHNH₂

4. None of the above

Aniline when diazotised in cold and then treated with dimethylaniline, gives a coloured product. It's structure would be :                                                                             

1.
 

2. 
 

3. 
 

4. 

Name the end product in the following series of reactions,

CH₃COOH $\stackrel{{\mathrm{NH}}_3}{\to }$A$\stackrel{∆}{\to }$B$\stackrel{{\mathrm{P}}_2{\mathrm{O}}_5}{\to }$C:

(a) CH₄                                         (b) CH₃OH

(c) acetonitrile                               (d) ammonium acetate

The type of isomerism shown by C₆H₅CN and C₆H₅NC is:

(a) position

(b) functional

(c) enantiomerism

(d) tautomerism

An organic compound A on reduction gives compound B which on reaction with chloroform and potassium hydroxide forms C. The compound C on catalytic reduction gives N-methylaniline. The compound A is                                                                                      [2000]

(a) nitrobenzene

(b) nitromethane

(c) methylamine

(d) aniline

An aromatic primary amine with cold nitrous acid leads to the formation of:

(a) alcohol

(b) nitrite

(c) diazonium salt

(d) benzene

Product P in the above reaction is 

[2002]

In the reaction,

${\mathrm{CH}}_3\mathrm{CN}+2\mathrm{H}\underset{{\mathrm{SnCl}}_2}{\overset{\mathrm{HCl}}{\to }}X \stackrel{\mathrm{Boiling} {\mathrm{H}}_2\mathrm{O}}{\to } Y,$ the term Y is 

[1999]

1. Acetone

2. Ethanamine

3. Acetaldehyde

4. Dimethyl amine

X and Y in the given reaction are:

(a) ${\mathrm{CH}}_3\mathrm{COOH} + ({\mathrm{CH}}_3{)}_2\mathrm{NH}$

(b) ${\mathrm{CH}}_3{\mathrm{CONH}}_2 + {\mathrm{CH}}_3\mathrm{OH}$

(c) ${\mathrm{CH}}_3\mathrm{CHO} + ({\mathrm{CH}}_3{)}_2\mathrm{NH}$

(d) ${\mathrm{CH}}_3{\mathrm{COCH}}_3 + {\mathrm{CH}}_3{\mathrm{NH}}_2$