Q. No.Which of the following steps are catalysed by Taq DNA polymerase in a PCR reaction?
1. Denaturation of template DNA
2. Annealing of primers to template DNA
3. Extension of primer end on the template DNA
4. All of the above
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A bacterial cell was transformed with a recombinant DNA molecule that was generated using a human gene. However, the transformed cells did not produce the desired protein. The reasons could be:
| 1. | Human genes may have intron which bacteria cannot process |
| 2. | Amino acid codons for humans and bacteria are different |
| 3. | Human protein is formed but degraded by bacteria |
| 4. | All of the above |
Which of the following should be chosen for the best yield if one were to produce a recombinant protein in large amounts?
| 1. | Laboratory flask of the largest capacity |
| 2. | A stirred-tank bioreactor without in-lets and out-lets |
| 3. | A continuous culture system |
| 4. | Any of the above |
Who among the following was awarded the Nobel Prize for the development of the PCR technique?
| 1. | Herbert Boyer | 2. | Hargovind Khurana |
| 3. | Kary Mullis | 4. | Arthur Kornberg |
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Which of the following statements does not hold true for restriction enzyme?
| 1. | It recognises a palindromic nucleotide sequence |
| 2. | It is an endonuclease |
| 3. | It is isolated from viruses |
| 4. | It can produce the same kind of sticky ends in different DNA molecules |
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Ti-plasmid is used for making transgenic plants. It is obtained from
1. Azotobacter
2. Agrobacterium
3. Rhizobium in leguminous root
4. Yeast
In transgenics, the expression of transgene in the target tissue is known by
1. Enhancer
2. Transgene
3. Promoter
4. Reporter
Production of human protein in bacterial genetic engineering is possible because
1. Human chromosome replicate bacterial cell
2. Mechanism of gene regulation is identical in humans and bacteria
3. Bacterial cell can undertake RNA splicing
4. Genetic code is universal
The linking of antibiotic resistance gene with the plasmid vector became possible due to
1. DNA polymerase
2. Exonucleases
3. DNA ligase
4. Endonucleases
Given below is a sample of a portion of DNA strand. What is so special shown in it
5' GAATTC 3'
3' CTTAAG 5'
1. Replication completed
2. Deletion mutation
3. Start codon at the 5' end
4. Palindromic sequence of base pairs
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