Telomeres with repetitive DNA sequences
1. Act as replicons
2. Are transcription initiators
3. Help in chromosome pairing
4. Prevent chromosome loss.
Test cross involves
1. Crossing between two genotypes with dominant trait
2. Crossing between two genotypes with recessive trait
3. Crossing the F1 hybrid with double recessive genotype
4. Crossing between two F1 hybrids.
Lack of independent assortment between two genes A and B would be due to
1. Crossing over
2. Linkage
3. Repulsion
4. Recombination.
Recessive gene present on one X- chromosome of humans will be
1. Lethal
2. Sublethal
3. Expressed in males
4. Expressed in females.
Genotype of hybrid is known by crossing
1. F2 progeny with female parent
2. F1 × F1
3. Crossing F1 with recessive parent
4. F2 with recessive parent.
In pea, yellow seed colour is dominant over green colour. Heterozygous yellow seeded plant is crossed with green seeded plant. The ratio of yellow & green seeded offspring will be
1. 9 : 1
2. 1 : 3
3. 3 : 1
4.50 : 50
A human male produces diallelic sperms in equal proportion AB, Ab, aB, and ab. The genotype of the person would be:
1. | Aa Bb | 2. | Aa BB |
3. | AA Bb | 4. | AA BB. |
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Which one of the following conditions in humans is correctly matched with its chromosomal abnormality/linkage ?
1. Erythroblastosisfetalis – X- linked
2. Down’s syndrome – 44 autosomes + XO
3. Klinefelter’ssyndrome – 44 autosomes + XXY
4. Colour blindness – Y-linked
Point mutation involves
1. Deletion
2. Insertion
3. Change in single base pair
4. Duplication
The most popularly known blood grouping is the ABO grouping. It is named ABO and not ABC, because “O” in it refers to having:
1. | No anitgens A and B on RBCs |
2. | Other antigens besides A and B on RBCs |
3. | Overdominance of this type on the genes for A and B types |
4. | One antibody only - either anti-A or anti-B on the RBCs |
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