Identify the product formed during the following reaction.

                  

1.           2.  

3.           4.  

Subtopic:  Isomers & Reaction Mechanism |
 52%
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Select the correct statement(s)

1.          2.  

3.           4.  

Subtopic:  Isomers & Reaction Mechanism |
 53%
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Which compound/compounds is/are optically active?

1.                        2.  

3.         4.  All of these

Subtopic:  Stereo Isomers |
 80%
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If 'A' and 'B' are major products then 'B' is

1.        2.  

3.             4.  

Subtopic:  Isomers & Reaction Mechanism |
 51%
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Formed product will give

(1)  Ceric ammonium nitrate and NaHCO3 test

(2)  NaHCO3 test and DNP test

(3)  NaHCO3 and Victor Meyer test

(4)  Both (A) & (C)

Subtopic:  Isomers & Reaction Mechanism |
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The incorrect method for the preparation of Me3COMe in good yield is

1. Me3CCl + MeONa →

2. \(Me_{2}C=CH_{2}\xrightarrow[(ii)NaBH_{4}]{(i) Hg(OAc)_{2}/MeOH}\)

3. Me3CONa + MeCl ⟶

4. \(Me_{2}C=CH_{2}\xrightarrow[MeOH]{H^{+}}\)

Subtopic:  Isomers & Reaction Mechanism |
 57%
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 Product of products

1.  R - COOH only

2.  R - CHO only

3.  R - CHO and R - COOH

4.             O      O
           ||      ||
  R  -C -  C - R

Subtopic:  Isomers & Reaction Mechanism |
 59%
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Number of secondary alcoholic groups that are attached to the ring in the major product of the given reaction is/are:

  

1.  Three

2.  Four

3.  Two

4.  One

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 59%
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An organic compound (A) of the molecular formula C6H12O3 gives a positive Iodoform test but does not reduce Tollen's reagent. When (A) is subjected to acid-catalyzed hydrolysis, another compound B is formed which gives positive Tollen's test. Identify the unknown compound (A).

1.       

2.  

3.  

4.  

Subtopic:  Name Reaction |
 56%
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PH - CHO CH3COONa/H2OCH3 - CO2OA 
The prodct A is

1.        2.   

3.          4.  

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 61%
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