If 'A' and 'B' are major products then 'B' is

1.        2.  

3.             4.  

Formed product will give

(1)  Ceric ammonium nitrate and ${\mathrm{NaHCO}}_3$ test

(2)  ${\mathrm{NaHCO}}_3$ test and DNP test

(3)  ${\mathrm{NaHCO}}_3$ and Victor Meyer test

(4)  Both (A) & (C)

The incorrect method for the preparation of Me₃COMe in good yield is

1. Me₃CCl + MeONa →

2. \(Me_{2}C=CH_{2}\xrightarrow[(ii)NaBH_{4}]{(i) Hg(OAc)_{2}/MeOH}\)

3. Me_3CONa + MeCl ⟶

4. \(Me_{2}C=CH_{2}\xrightarrow[MeOH]{H^{+}}\)

 Product of products

1.  R - COOH only

2.  R - CHO only

3.  R - CHO and R - COOH

4.  $O O$
$\left|\right| \left|\right|$
$R -C - C - R$

1.  Three

2.  Four

3.  Two

4.  One

An organic compound (A) of the molecular formula ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_3$ gives a positive Iodoform test but does not reduce Tollen's reagent. When (A) is subjected to acid-catalyzed hydrolysis, another compound B is formed which gives positive Tollen's test. Identify the unknown compound (A).

1.       

2.  

3.  

4.  

$\mathrm{PH} - \mathrm{CHO} \underset{{\mathrm{CH}}_3\mathrm{COONa}/{\mathrm{H}}_2\mathrm{O}}{\overset{{\left({\mathrm{CH}}_3 - \mathrm{CO}\right)}_2\mathrm{O}}{\to }}\left(\mathrm{A}\right)$
$\mathrm{The} \mathrm{prodct} \mathrm{A} \mathrm{is}$

1.        2.   

3.          4.  

${\mathrm{C}}_2{\mathrm{H}}_4\stackrel{{\mathrm{O}}_3/\mathrm{Zn}/{\mathrm{H}}_2{\mathrm{O}}_2}{\to } \mathrm{Product} \left(\mathrm{A}\right)$

Product (A) can give

1. Haloform test

2. Aldol condensation

3. Cannizaro reaction

4. Both (A) & (B)

Consider the following reaction,



The B and C are respectively:

1.  RCHO and HCHO

2.  RCOOH and HCOOH

3.   RCH₂OH and CH₃OH

4. 

${\mathrm{CH}}_3{\mathrm{NO}}_2\stackrel{\left(3{{\mathrm{Cl}}_{2_{}}}_{}+ 3\mathrm{NaOH}\right)}{\to } \mathrm{P}. \text{'}\mathrm{P}\text{'} \mathrm{is}$

1. ${\mathrm{CCl}}_3\mathrm{CHO}$

2. ${\mathrm{CCl}}_3{\mathrm{NO}}_2$

3. ${\mathrm{CHCl}}_3$

4. ${\mathrm{CHCl}}_2{\mathrm{NO}}_2$