Ozonolysis of buta-1,3-diene gives:

1. HCHO and glyoxal

2. ${\mathrm{CH}}_3\mathrm{CHO}$ and glyoxal

3. ${\mathrm{CO}}_2$ and glyoxal

4. HCHO + glyoxal + ${\mathrm{CH}}_3\mathrm{CHO}$

Hydroxylation of propyne in the presence of ${\mathrm{HgSO}}_4/{\mathrm{H}}_2{\mathrm{SO}}_4$ is initiated by the attack of:

1. Carbene                                   

2. Free radical

3. Electrophile                               

4. Nucleophile

Ethylene forms ethylene chlorohydrin by the action of:

1. Dry chlorine gas

2. Dry hydrogen chlorine gas

3. Solution of chlorine gas in water

4. Dilute hydrochloric acid 

Acetylenic hydrogens are acidic because

1. Sigma electron density of C-H bond in acetylene is nearer to carbon which has 50% s-character

2. Acetylene has only one hydrogen on each carbon

3. Acetylene contains least number of hydrogens among the possible hydrocarbons having two carbons

4. Acetylene belong to the class of alkynes with molecular formula ${\mathrm{C}}_{\mathrm{n}}{\mathrm{H}}_{2\mathrm{n}-2}$

When acetylene is passed through dil. ${\mathrm{H}}_2{\mathrm{SO}}_4$ in presence of ${\mathrm{HgSO}}_4$, the compound formed is

1. Ether                                    2. Ketone

3. Acetic acid                             4. Acetaldehyde

Consider the following reaction sequence: 

 ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_3\stackrel{\mathrm{Oxidation}}{\to }$ (A)  $\stackrel{\mathrm{NaOH}}{\to }$ (B) $\underset{∆}{\overset{\mathrm{Soda} \mathrm{lime}}{\to }}$ (C)

The product (C) is:

The reaction of toluene with ${\mathrm{Cl}}_2$ in the presence of ${\mathrm{FeCl}}_3$ gives 'X' and reaction in presence of light gives 'Y'. Thus, 'X' and  'Y' are:

1. X = Benzal chloride, Y= o-chlorotoluene

2. X = m-Chlorotoluene, Y= p-Chlorotoluene

3. X = o and p-Chlorotoluene, Y = Trichloromethyl benzene

4. X = Benzal chloride, Y = m-Chlorotoluene

3-hexyne can be converted to trans-3-hexene by the action of:

1. ${\mathrm{H}}_2$ - Pd/ ${\mathrm{BaSO}}_4$                       2. Li-Liq. ${\mathrm{NH}}_3$

3. ${\mathrm{H}}_2$ - Pt ${\mathrm{O}}_2$                                4. ${\mathrm{NaBH}}_4$

CH₃-C$\equiv$C-H$\stackrel{{\mathrm{CH}}_3\mathrm{MgBr}}{\to }$CH₄ + (A)$\underset{\left(\mathrm{ii}\right) {\mathrm{H}}_2\mathrm{O}/{\mathrm{H}}^{+}}{\overset{\left(\mathrm{i}\right) {\mathrm{CO}}_2}{\to }}$(B); (B) will be

1. H₃C-CH₂-CH₂-COOH                                2. CH₃-C$\equiv$C-CH₃

3. H₃C-C$\equiv$C-COOH                                     4. H₃C-CH=CH-COOH

In Friedel-Craft's alkylation, besides AlCl₃, the other reactants are                             

1. C₆H₆ + NH₃

2. C₆H₆ + CH₄

3. C₆H₆ + CH₃Cl

4. C₆H₆ + CH₃COCl