Chloroform on reduction with Zn and HCl (alc.) gives:-

1. Formic acid

2. Chloretone

3. Chloropicrin

4. Methylene dichloride

Freon (CCl₂F₂) can be produced by:

1. C + F₂ + Cl₂ $\to$

2. CH₃Cl + F₂ $\to$

3. CCl₄ + HF $\stackrel{{\mathrm{SbCl}}_5}{\to }$

4. CCl₄ + F₂ $\to$

$\stackrel{\mathrm{Moist} {\mathrm{Ag}}_2\mathrm{O}}{\to }$ (A) product

Major product (A) is:

1.  

2. 

3. 

4. 

1-2-dichloro ethane + NaSCH₂CH₂SNa $\to$NaCl + (P)

Unknown product (p) of the above reaction is:

1. 

2. 

3. $\mathrm{H}-\mathrm{S}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{S}-\mathrm{H}$

4. $\mathrm{H}-\mathrm{CH}=\mathrm{CH}-{\mathrm{CH}}_2-\mathrm{S}-\mathrm{H}$

$\underset{\mathrm{EtOH},∆}{\overset{\mathrm{KOH}}{\to }}\underset{\left(major\right)}{\left(A\right)}$

Product (A) is:

1.

2.

3.

4.

Product A is:

1.		2.
3.		4.

(A)In the above reaction, maximum Saytzeff product will obtained when
     (a) X = I    (b) X = -Cl      (c) X = -Br       (d) X = -F

(B) In the above reaction Hofmann product is major when X is:
      (a) -I          (b) -Cl            (c) -Br             (d) -F

1. A- a , B - d

2. A- b, B - c

3. A -c , B - a 

4. A - d, B -d

Major product of the above reaction is:

1. 

2. 

3. 

4. 

Major product is :-
 

1.         
2. 

3.           
4.

Addition of KI accelerates the hydrolysis of primary alkyl halides because:

1. KI is soluble in organic solvents

2. The iodide ion is a weak base and a poor leaving group

3. The iodide ion is a strong base

4. The iodide ion is a powerful nucleophile as well as a good leaving group