$\stackrel{\mathrm{dilute} {\mathrm{OH}}^{-}}{\to }?$

The major product formed would be

The correct order of increasing reactivity towards
acid hydrolysis is
$\underset{\left(1\right)}{{\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5} \underset{\left(2\right)}{C{H}_{3}COCl } \underset{\left(3\right)}{C{H}_{3}CONHC{H}_3}$

1. 1 < 2 < 3

2. 3 < 1 < 2

3. 1 < 3 < 2

4. 2 < 1 < 3

I.    R₁ = H             II R₁ = CH₃

      R₂ = CH₃             R₂ = -CH(CH₃)₂

III. R₁ = CH₃          IV R₁ = CH₃

      R₂ = CH₃              R₂ = C₂H₅

The rate of addition follows the order

1. I > II > III > IV

2. I > III > IV > II

3. I > III > II > IV

4. I > II > IV > III

The end product of the following reaction would be

$\underset{\left(\mathrm{ii}\right) ∆}{\overset{\left(\mathrm{i}\right) {\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }}$

Which acid is least reactive to decarboxylation when heated?

1.		2.
3.		4.

When glycerol is reacted with oxalic acid at 260^oC, then the final product formed is

1. Formic acid

2. Allyl alcohol

3. Acrolein

4. Acetic Acid

When propanoic acid is treated with aqueous sodium bicarbonate, CO₂ is liberated. The ‘C’ of CO₂ comes from:

1. Carboxylic acid group

2. Methylene group

3. Bicarbonate

4. Methyl group

In the reaction

${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CHO}\underset{\mathrm{agent}}{\overset{\mathrm{oxidizing} }{\to }}$
${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{COOH}$

the oxidizing agent can be

1. Alkaline KMnO₄

2. Acidified K₂Cr₂O₇

3. Benedict’s solution

4. All of the above

The appropriate reagent for the transformation is

1. Zn (Hg)/HCl

2. NH₂–NH₂/OH^–

3. Both 1. and 2.

4. None of the above

In a Cannizzaro’s reaction, the intermediate that will
be the best hydride donor is