A compound X having the molecular formula C3H9N
reacts with benzene sulphonyl chloride to form a solid
that is insoluble in alkalies. The compound X is
1. CH3CH2CH2NH2
2. (CH3)2CHNH2
3. CH3CH2NHCH3
4. (CH3)3N

Subtopic:  Identification of Primary, Secondary & Tertiary Amines |
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Mendius reaction involves the reduction of :
1. Cynoalkanes

2. Alkyl isocyanides

3. Oximes

4. Nitroalkanes

Subtopic:  Amines - Preparation & Properties |

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BSnCl2+HClNH4HSA

The product A and B are:

 

 

Subtopic:  Amines - Preparation & Properties |

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Aniline    o-toluidine     m-toluidine    p-toluidine
(I)              (II)               (III)              (IV)

Correct order of basic strength of the above
compounds is

1. II > IV > III > I

2. IV > III > I > II

3. III > II > IV > I

4. IV > I > III > II

Subtopic:  Amines - Preparation & Properties |
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0°-5°CNaNO2+HClX moles of N2 gas

Hence, the value of ‘X’ is

1. 4

2. 3

3. 2

4. 1

Subtopic:  Diazonium Salts: Preparation, Properties & Uses |
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Identify the product (c) in the series

CH3CNNa/C2H5OHAHNO2BKMnO4,H+C

1. CH3COOH

2. CH3CH2NHOH

3. CH3CONH2

4. CH3CHO

Subtopic:  Amines - Preparation & Properties | Diazonium Salts: Preparation, Properties & Uses |
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An amide (A) C3H7NO on hydrolysis gives an amine
(B) and an acid (C). B gives carbylamine reaction
where as C reduces Tollen’s reagent. (A) is

1. CH3CONHCH3

2. CH3CH2CONO2

3. HCONHC2H5

4. HCONCH32

Subtopic:  Amines - Preparation & Properties |

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The amine that reacts with Hinsberg's reagent to give an alkali insoluble product is:-

1. CH3CHNHCHCH3
         |           |
         CH3    CH3

2.                  CH2CH3
                 |
CH3CH2NCH2CH3

3.          NH2
         |
CH3CCH2CH2CH3
         |
        CH3

4.          CH3
          |
CH3COCHNH2
         |    |
        CH3CH3

Subtopic:  Identification of Primary, Secondary & Tertiary Amines |
 78%
From NCERT
NEET - 2019
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The correct order of the basic strength of methyl substituted amines in aqueous solution is:

1.  CH3NH2 > CH32 NH >CH33 N

2.  CH32 NH > CH3NH2 >CH33 N

3.  CH33 N > CH3NH2 >CH32 NH

4.  CH32 N > CH32 N >CH3NH2

Subtopic:  Amines - Preparation & Properties |
 81%
From NCERT
NEET - 2019
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Which of the following is more basic than aniline? 
 

1. Diphenylamine

2. Triphenylamine

3. p-nitroaniline

4. Benzylamine

Subtopic:  Amines - Preparation & Properties |
 73%
From NCERT
AIPMT - 2006
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