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Among the following options, which diazonium salt would be the most stable?
1.
2.
3.
4.
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Method by which aniline cannot be prepared is
1. Hydrolysis phenyl isocyanide with acidic solution
2. Degradation of benzamide with bromine in alkaline Solution
3. Reduction of nitrobenzene with H/Pd in ethanol
4. Potassium salt of phthalimide treated with chlorobenzene followed by the hydrolysis aqueous NaOH solution
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1. | Arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalized by interaction with the aromatic ring -electron system |
2. | Arylamines are generally more basic than alkylamines because of aryl group |
3. | Arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridlzed |
4. | Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring -electron system. |
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A given nitrogen-containing aromatic compound A reacts with Sn/HCl, followed by HNO2 to give an unstable compound B. B, on treatment with phenol, forms a beautiful coloured compound C with the molecular formula C12H10N2O . The structure of compound A is-
1.
2.
3.
4.
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Which one of the following nitro-compounds does not react with nitrous acid
1.
2.
3.
4.
Nitration of aniline in strong acidic medium also gives m-nitroaniline because
1. In spite of substituents nitro group always goes to only m-position
2. In electrophilic substitution reactions amino group is meta directive
3. In absence of substituents nitro group always goes to only m-position
4. In acidic (strong) medium aniline is present as anilinium ion
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