Which of the following is not true for this progressive wave y=4sin2πt0.02x100 where y and x are in cm and t in sec 

(1) Its amplitude is 4 cm

(2) Its wavelength is 100 cm

(3) Its frequency is 50 cycles/sec

(4) Its propagation velocity is 50 × 104 cm/sec

Subtopic:  Wave Motion |
 74%
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The phase difference between two waves represented by y1=106sin[100t+(x/50)+0.5]m, y2=106cos[100t+(x/50)]m where x is expressed in metres and t is expressed in seconds, is approximately:

(1) 1.5 rad

(2) 1.07 rad

(3) 2.07 rad

(4) 0.5 rad

Subtopic:  Wave Motion |
 60%
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A particle on the trough of a wave at any instant will come to the mean position after a time (T = time period) 

(1) T/2

(2) T/4

(3) T

(4) 2T

Subtopic:  Wave Motion |
 76%
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Two sound waves (expressed in CGS units) given by y1=0.3sin2πλ(vtx) and y2=0.4sin2πλ(vtx+θ) interfere. The resultant amplitude at a place where the phase difference is π/2 will be :

(1) 0.7 cm

(2) 0.1 cm

(3) 0.5 cm

(4) 1107cm

Subtopic:  Wave Motion |
 86%
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The amplitude of a wave represented by displacement equation y=1asinωt±1bcosωt will be

(1) a+bab

(2) a+bab

(3) a±bab

(4) a+bab

Subtopic:  Wave Motion |
 77%
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When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork is :

(1) 334

(2) 339

(3) 343

(4) 347

Subtopic:  Beats |
 76%
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When two sound waves are superimposed, beats are produced when they have :

(1) Different amplitudes and phases

(2) Different velocities

(3) Different phases

(4) Different frequencies

Subtopic:  Beats |
 78%
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It is possible to hear beats from the two vibrating sources of frequency :

(1) 100 Hz and 150 Hz

(2) 20 Hz and 25 Hz

(3) 400 Hz and 500 Hz

(4) 1000 Hz and 1500 Hz

Subtopic:  Beats |
 83%
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Two vibrating tuning forks produce progressive waves given by Y1=4sin500πt and Y2=2sin506πt. Number of beats produced per minute is :

(1) 360

(2) 180

(3) 3

(4) 60

Subtopic:  Beats |
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A wave represented by the given equation y=acos(kxωt) is superposed with another wave to form a stationary wave such that the point x = 0 is a node. The equation for the other wave is :

(1) y=asin(kx+ωt)

(2) y=acos(kx+ωt)

(3) y=acos(kxωt)

(4) y=asin(kxωt)

Subtopic:  Standing Waves |
 52%
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