A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by T=2πlg',  where g'   is equal to

(1) g                                                       

(2) g-a

(3) g+a

(4) g2+a2

Subtopic:  Angular SHM |
 88%
From NCERT
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If the length of second's pendulum is decreased by 2%, how many seconds it will lose per day?

1. 3927 sec

2. 3727 sec

3. 3427 sec

4. 864 sec

Subtopic:  Simple Harmonic Motion |
 68%
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In a simple pendulum, the period of oscillation T is related to length of the pendulum l as

(1) lT=constant

(2) l2T=constant

(3) lT2=constant

(4) l2T2=constant

Subtopic:  Angular SHM |
 83%
From NCERT
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The equation of motion of a particle is \({d^2y \over dt^2}+Ky=0 \) where \(K\) is a positive constant. The time period of the motion is given by: 
1. \(2 \pi \over K\) 2. \(2 \pi K\)
3. \(2 \pi \over \sqrt{K}\) 4. \(2 \pi \sqrt{K}\)
Subtopic:  Simple Harmonic Motion |
 76%
From NCERT
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The kinetic energy of a particle executing SHM is \(16~\text{J}\) when it is in its mean position. If the amplitude of oscillations is \(25~\text{cm}\) and the mass of the particle is \(5.12~\text{kg}\), the time period of its oscillation will be:
1. \(\frac{\pi}{5}~\text{s}\)
2. \(2\pi ~\text{s}\)
3. \(20\pi ~\text{s}\)
4. \(5\pi ~\text{s}\)
Subtopic:  Energy of SHM |
 71%
From NCERT
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A pendulum has time period T. If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth then its time period on the other planet will be

(1) T

(2) T

(3) T1/3

(4) 2T

Subtopic:  Angular SHM |
 85%
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A particle in SHM is described by the displacement equation xt=Acos ωt+θ. If the initial position of the particle is 1 cm and its initial velocity is πcm/s, what is its amplitude? (The angular frequency of the particle is π s-1)

(1)  1 cm       

(2)  2 cm

(3)  2 cm     

(4)  2.5 cm

Subtopic:  Simple Harmonic Motion |
 62%
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A simple pendulum hanging from the ceiling of a stationary lift has a time period T1. When the lift moves downward with constant velocity, the time period is T2, then

(1) T2 is infinity

(2) T2>T1

(3) T2<T1

(4) T2=T1

Subtopic:  Angular SHM |
 60%
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If the length of a pendulum is made 9 times and mass of the bob is made 4 times , then the value of time period becomes

(1) 3T

(2) 3/2T

(3) 4T

(4) 2T

Subtopic:  Angular SHM |
 88%
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A simple harmonic wave having an amplitude a and time period T is represented by the equation y=5 sinπt+4m Then the value of amplitude (a) in (m) and time period  (T) in second are       

(1) a=10, T=2   

(2) a=5, T=1

(3) a=10, T=1    

(4) a=5, T=2

Subtopic:  Simple Harmonic Motion |
 88%
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