When vinyl chloride is passed through an alcoholic KOH solution, which of the following is correct?

1. It gets dissolved.                              

2. It forms vinyl alcohol

3. It forms acetylene                     

4. It has no action

(CH₃)₃CMgCl on reaction with D₂O gives:

1. (CH₃)₃CD

2. (CH₃)₃OD

3. (CD₃)₃CD

4. (CD₃)₃OD

The product (C) in the below-mentioned reaction is:
\(CH_{3}CH_{2}CH_{2}Br \ \xrightarrow[]{\textbf{KOH(alc.)}} \)
\(\ (A) \ \xrightarrow[]{\textbf{HBr}} \ (B) \ \xrightarrow[]{\textbf{KOH(aq}} \ (C)\)

The reaction of toluene with ${\mathrm{Cl}}_2$ in presence of ${\mathrm{FeCl}}_3$ gives predominantly :

1. m- chlorobenzene                   

2. benzoylchloride

3. benzyl chloride                         

4. O^- and p-chlorotoluene                    

Arrange the following halides in the decreasing order of ${\mathrm{S}}_{\mathrm{N}}1$ reactivity

(I) ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{Cl}$

(II) ${\mathrm{CH}}_2=\mathrm{CHCH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$

(III) ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}\left(\mathrm{Cl}\right){\mathrm{CH}}_3$

1. I>II>III                            2. II>I>III

3. II>III>I                            4. III>II>I

Arrange the following compouds in the order of leaving group ability

1. I > II > III > IV

2. IV > III > I > II

3. III > II > I > IV

4. II > III > IV > I

Which of the following alkyl halide undergo rearrangement in SN1 reaction?

1. $\begin{array}{ccccccc}{\mathrm{CH}}_3& -& \underset{{\mathrm{CH}}_3}{\underset{|}{\stackrel{{\mathrm{CH}}_3}{\stackrel{|}{\mathrm{C}}}}}& -& \underset{\mathrm{I}}{\underset{|}{\mathrm{CH}}}& -& {\mathrm{CH}}_3\end{array}$

2.  

3.  

4. All of these

$\underset{{\mathrm{S}}_{\mathrm{N}}2 \mathrm{conditions}}{\overset{\mathrm{LiBr}}{\to }}Major product$

The product X is :-

1.         2. 

3.            4.

Anisole$\underset{\mathrm{reflux}}{\overset{\mathrm{excess} \mathrm{HI} (\mathrm{conc}.)}{\to }}$Product

1. 

2. 

3. 

4. 

\(HC\equiv CNa \ + \ Cl-CH_{2}-CH_{2}-CH_{2}-I \ \rightarrow \ (A) \)
The major product (A) in the above reaction is :

1. H-C$\equiv$C-CH₂-CH₂-CH₂-I

2. CH₂=CH-CH₂-I

3. H-C$\equiv$C-CH₂-CH₂-CH₂-Cl

4. CH₂=CH-CH₂-Cl