Benzaldehyde and acetaldehyde can be distinguished by:

1. Iodoform test

2. 2:4 DNP test

3. ${\mathrm{NH}}_3$ reaction

4. Wolff-Kishner's reduction

Acetaldehyde reacts with                

1. only electrophiles

2. only nucleophiles

3. only free radicals

4. both electrophiles and nucleophiles

Nucleophilic addition reaction will be most favoured in                   [2006]

(1) $$
$\mathrm{O}$
$\parallel$
${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2\mathrm{C}-{\mathrm{CH}}_3$

(2) $({\mathrm{CH}}_3{)}_2\mathrm{C}=\mathrm{O}$

(3) ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CHO}$

(4) ${\mathrm{CH}}_3\mathrm{CHO}$

What is present in acetone's enolic form?

1. 9 $\mathrm{\sigma }$-bonds, 1$\mathrm{\pi }$-bond and 2 lone pairs

2. 8 $\mathrm{\sigma }$-bonds, 2$\mathrm{\pi }$-bonds and 2 lone pairs

3. 10 $\mathrm{\sigma }$-bonds, 1$\mathrm{\pi }$-bond and 1 lone pair

4. 9 $\mathrm{\sigma }$-bonds, 2$\mathrm{\pi }$-bonds and 1 lone pair

In this reaction,

CH₃CHO + HCN $\to$CH₃CH(OH)CN $\stackrel{\mathrm{H}.\mathrm{OH}}{\to }$CH₃CH(OH)COOH

an asymmetric compound is generated. The acid obtained would be            

1. 50% D + 50% L-isomer

2. 20% D + 80% L-isomer

3. D-isomer

4. L-isomer

Which compound, upon hydrolysis of its cyanohydrin, yields lactic acid?

1. Acetone                                 

2. Acetaldehyde

3. Propanal                                 

4. HCHO

Formaldehyde can be distinguished from acetaldehyde by:

(a) Fehling's solution                     

(b) Schiff's reagent

(c) Ammonia                               

(d) Ammoniacal ${\mathrm{AgNO}}_3$

Consider the following reaction,

The reaction is fastest when X is-

1. Cl

2. NH₂

3. OC₂H₅

4. OCOR

In a set of reaction propionic acid yielded a compound D.

CH3CH2COOH$\stackrel{{\mathrm{SOCl}}_2}{\to }$ B$\underset{∆}{\overset{N{H}_3}{\to }}$ C$\underset{{\mathrm{Br}}_2}{\overset{\mathrm{KOH}}{\to }}$
$$

The structure of D would be

1. CH₃CH₂NHCH₃

2. CH₃CH₂NH₂

3. CH₃CH₂CH₂NH₂

4. CH₃CH₂CONH₂

$\stackrel{\mathrm{Zn}-\mathrm{Hg}/\mathrm{HCl}}{\to }$Product, Product is

1.  

2.

3.    

4.